Effacer les filtres
Effacer les filtres

How to get a period of cosinus function ?

3 vues (au cours des 30 derniers jours)
Ilan Moshe
Ilan Moshe le 25 Mai 2020
Commenté : Ilan Moshe le 27 Mai 2020
Hi,
I have to find the period of the cosinus function using only the vector time and the vector data of the function.
Cosinus function
Vector data
time data
  2 commentaires
Rik
Rik le 25 Mai 2020
This looks like the sum of two cosines, not just one. Do you want the cosine with the largest magnitude? Are you allowed to use a Fourrier transform?
Ilan Moshe
Ilan Moshe le 25 Mai 2020
Yes, it is actually a sum of cosines by using this code :
function [t,x]=getSumOfCosines(delta_t,Tlim,f)
t=0:delta_t:Tlim;
x=sum(cos(2*pi*t.*f));
end
The only restriction is to not use any loop and to use only x and t vectors.

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Rik
Rik le 25 Mai 2020
Modifié(e) : Rik le 25 Mai 2020
Because this is homework, I won't provide a copy-paste ready solution.
If you follow the example from the documentation for fft, you get the code below.
%recreate data
delta_t=0.1;Tlim=5;f=[1;2];
t=0:delta_t:Tlim;
x=sum(cos(2*pi*t.*f));
%figure(1),clf(1)
%plot(t,x)
Fs=1/mean(diff(t));%sampling frequency
L=numel(x);
Y = fft(x);
P2 = abs(Y/L);
P1 = P2(1:floor(L/2)+1);
f = Fs*(0:(L/2))/L;
figure(1),clf(1)
plot(f,P1,'-*')
title('Fourrier transform'),xlabel('frequency'),ylabel('magnitude')
Now you can clearly see there are two frequencies that have a high magnitude.
  3 commentaires
Rik
Rik le 25 Mai 2020
Frequency is the inverse of period.
Ilan Moshe
Ilan Moshe le 27 Mai 2020
Thanks :)

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