scope of disp()

Hi there,

I am trying to call a function that uses several calls to disp() to print out several messages to the workspace. Let's call this function "function B". So, function B then gets called from function A. The problem?

When I call function B from the workspace, function B displays the messages correctly, but when I call function A from the workspace (which then calls function B), none of the messages show. How can I get the messages to show even if I call function B from another function?

Thanks in advance,

-E.

[Oleg Komarov]

I don't get this problem. Did you place function B within a if statement inside of function A?

[Robert Cumming]

sounds like function B is not getting called...

Put a break in the code to check that it is (or isn't...)

[Elisa]

it is like this. I have a function, myfunctionB, that looks, more or less, like the listing below.

-0-0-0-0-0-0-

function [a, b] = myfunctionB(input)

a=3*input; b=4; disp('hello');

-0-0-0-0-0-

Very simple, no ifs, etc, just a display.

Then I have file myscriptA.m where I do

-0-0-0-0-0-0

disp('Now I'm going to call function B') [k, z] = myfunctionB(3);

-0-0-0-0-0-0-0-

But I never see hello displayed when I call myscriptA from the command line. If I just call myfunctionB from the command line, I get: >>hello

Like it should do, but not when function B is being called. Even tough it DOES get called.

Answer 1

[Andrew Newell]

Did you notice an error message? A quote in the middle of a string should be represented by two quotes. Try this:

disp('Now I''m going to call function B')
[k, z] = myfunctionB(3);

Answer 2

[Elisa]

Nevermind, you guys were right! As it turns out myfunctionB wasn't as simple, I was calling it in such a way to execute a path with no display messages (the function is more complicated than what I wrote up there, actually), so they weren't showing because indeed the display path wasn't executing. Sorry for the bother guys.

[Andrew Newell]

Feel free to accept this answer (just click on the Accept button).