Effacer les filtres
Effacer les filtres

ODE23s, Differential equation, problem solving

1 vue (au cours des 30 derniers jours)
Iro Malefaki
Iro Malefaki le 27 Mai 2020
Hello everybody. I have a serious problem solving the diff. equation, expressed below. Any help;
function [kap, alf0, Pstar, Astar]= nofilter()
imu=sqrt(-1);
rho=1000;RR=0.3;
Jb=0.1; %diastato
CC=0.1;%diastato
chr=0.1;
cht=0.1;
U=0.5;
span=0.34/2;
alam1=90;
alam2=90;
chm=0.5*(chr+cht);
span3d=2*span;
area=2*(chm*span);
AR=(span3d^2)/area;
AR=10;
B=14.75; %adiastato
BB=B*rho*U*0.34*chr*chr*RR; %diastato
pic=0.25;
II=Jb/pi*rho*area*chr*chr*chr; %adiastato
C=CC/1/2*pi*rho*area*chr*U^2; %adiastato
a=span3d*RR^2/chr*area;
b=RR^2/chr^2;
e=RR/chr;
d=RR*span3d/area;
alf0=linspace(1, 60, 2);
kap=linspace(0.025,0.2,2);
for i=1:length(alf0)
for j=1:length(kap)
om(j)=pi*kap(j)*2*U/chr; % reduced velocity k, Huxham, k=pi*khuxham
T(j)=2*pi/om(j);
alf0r(i)=alf0(i)*pi/180;
theo(j)=besselh(1,2,kap(j))./(besselh(1,2,kap(j))+imu*besselh(0,2,kap(j))); %theo function, lift deficiency factor
Re=U*chr*10^6; %reynolds
CD0=0.075/(log10(Re)+2)^2; %skin friction
fprintf('Calculating for %d\n', i, j);
[t,y]=ode23s(@(t,y) nofilter(t,y, i, j), [0 , 100],[0, 0]);
[Astar(i,j), Pstar(i,j)] = processsignal(t,y);
Pstar(i,j) = 0.5*BB.*(Pstar(i,j))./0.5*rho* 2*RR.*(Astar(i,j)).*cos(((Astar(i,j)))).*U^3;
end
end
function dYdt=nofilter(t,Y, i, j)
thi(i,j)=alf0r(i).*cos(om(j)*t);
k1=8*II+2*a*cos(thi(i,j)).*(cos(Y(1))-Y(1)*sin(Y(1)));
dYdt=[Y(2);(1/k1)*((Y(2)).*(-2*B+theo(j).*(AR/AR+2).*b.*cos(thi(i,j)).*(-cos(Y(1)+Y(1).*sin(Y(1)))))+...
(Y(2).^2)*2*a*cos(thi(i,j))*(2*sin(Y(1))*Y(1)+Y(1)*cos(Y(1)))-Y(1)*C+...
theo(j)*(AR/AR+2)*e*(thi(i,j).*cos(thi(i,j))+(3/4-pic)*2*thi(i,j).*cos(thi(i,j)))+...
d*(thi(i,j)+(1/2-pic)*2*thi(i,j).*cos(thi(i,j)))-e*(1/pi)*sin(thi(i,j))*(CD0+1.6*(thi-atan(2*e*Y(2).*(cos(Y(1))-Y(1).*sin(Y(1))))).^2))];
end
end
function [Aout,Pstar] = processsignal(t,y)
% process signal
Y = y(:,1);
Ydot = y(:,2);
k = 2:length(Y)-1;
Kmax = find( Y(k)>Y(k-1) & Y(k)>Y(k+1) );
Kmax = Kmax+1; %correct index
Kmin = find( Y(k)<Y(k-1) & Y(k)<Y(k+1) );
Kmin = Kmin+1; %correct index
ti_max = 0.5*(t(Kmax(1:end-1))+t(Kmax(2:end)));
ti_min = 0.5*(t(Kmin(1:end-1))+t(Kmin(2:end)));
N = 5; % number of final cycles for averagingaw
Aout = 0.5*(mean(Y(Kmax(end-N,end))) - mean(Y(Kmin(end-N,end))));
subplot(2,1,1), plot(t,Y,t(Kmax),Y(Kmax),'ob',t(Kmin),Y(Kmin),'ob')
subplot(2,1,2), plot(t(Kmax),Y(Kmax),'o',t(Kmin),abs(Y(Kmin)),'o')
Jint = find(t>=t(Kmax(end-N)) & t<t(Kmax(end)));
Pstar = (1/4)*trapz(t(Jint),Ydot(Jint).^2); % integral,1/4
end

Réponses (0)

Catégories

En savoir plus sur Programming dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by