need help with my code
Afficher commentaires plus anciens
I have my code almost completed but i need to do a variation plot and i was given three different values for phi. Phi = 0, 45, 85 (degress). My question is how can i add the other values for phi in this code
delta = 35;
phi = 0;
L = 384329*1000;
re = 6376*1000;
Me = 5.98e24;
Mm = 7.34e22;
lambda = [0:5:360];
T1 = (re/4)*(Mm/Me)*(re/L)^3;
T2 = 3*((sind(phi))^2)*(sind(delta))^2-1;
T3 = 3/2*sind(2*phi)*sind(2*delta)*cosd(lambda);
T4 = 3*(cosd(phi))^2*(cosd(delta))^2*(cosd(lambda)).^2;
eta = T1*(T2+T3+T4);
figure(1)
plot(lambda,eta)
grid on
xlabel('\lambda(degrees)')
ylabel('\eta(m)')
title('\eta(m) Vs. \lambda(degrees) when \phi is 0(degrees)')
Réponses (1)
Image Analyst
le 28 Mai 2020
Modifié(e) : Image Analyst
le 28 Mai 2020
Try this:
clc; % Clear the command window.
fprintf('Beginning to run %s.m.\n', mfilename);
close all; % Close all figures (except those of imtool.)
clear; % Erase all existing variables. Or clearvars if you want.
workspace; % Make sure the workspace panel is showing.
format long g;
format compact;
fontSize = 22;
delta = 35;
allPhi = [0, 45, 85]
L = 384329*1000;
re = 6376*1000;
Me = 5.98e24;
Mm = 7.34e22;
lambda = [0:5:360];
T1 = (re/4)*(Mm/Me)*(re/L)^3;
for k = 1 : length(allPhi)
phi = allPhi(k);
T2 = 3*((sind(phi))^2)*(sind(delta))^2-1;
T3 = 3/2*sind(2*phi)*sind(2*delta)*cosd(lambda);
T4 = 3*(cosd(phi))^2*(cosd(delta))^2*(cosd(lambda)).^2;
eta = T1*(T2+T3+T4);
subplot(2, 2, k);
plot(lambda,eta, 'b-', 'LineWidth', 2);
grid on
xlabel('\lambda(degrees)', 'FontSize', fontSize);
ylabel('\eta(m)', 'FontSize', fontSize);
% title('\eta(m) Vs. \lambda(degrees) when \phi is 0(degrees)', 'FontSize', fontSize);
caption = sprintf('\\eta(m) Vs. \\lambda(degrees) when \\phi is %.1f(degrees)', phi); % Use double backslashes.
title(caption, 'FontSize', fontSize);
end
g = gcf;
g.WindowState = 'maximized'
fprintf('Done running %s.m.\n', mfilename);

Catégories
En savoir plus sur Creating, Deleting, and Querying Graphics Objects dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!