speed up intersect, setdiff functions

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priyan
priyan le 15 Nov 2012
Commenté : Chinmaya KA le 9 Sep 2020
Hi
I have some code, which when I examine using the Matlab Profiler shows that the majority of the time is spent on the intersect and setdiff functions, which are invoked many times during a looping process. I was wondering if there was a clever way to speed this up? For example is it possible to somehow vectorize the following code to avoid invoking the inbuilt set functions? Thanks for your help!
tic;
size=50000;
a=round(100*rand(size,1));
b=round(100*rand(size,1));
intersect(a,b);
setdiff(a,b);
toc;
  1 commentaire
Matt Fig
Matt Fig le 15 Nov 2012
Your best bet might be to avoid performing these operations in a loop in the first place...

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Réponse acceptée

Jan
Jan le 15 Nov 2012
intersect and setdiff both sort the inputs. Therefore you can omit at least one sorting, when you copy the relevant parts of both function to a new file. Then ismembc will do its work once, as Sean has suggested already.

Plus de réponses (2)

Jonathan Epperl
Jonathan Epperl le 15 Nov 2012
If your sets aren't much larger than your example, and are indeed made up of positive integers, then those two functions here can get you a drastic increase in speed. The idea isn't mine, afaik Kevin Murphy of the Bayes Net TB came up with it. Anyway, 2 functions which pretty much exactly replace setdiff and intersect (as long as you work with positive integers):
function C = MY_intersect(A,B)
if ~isempty(A)&&~isempty(B)
P = zeros(1, max(max(A),max(B)) ) ;
P(A) = 1;
C = B(logical(P(B)));
else
C = [];
end
and
function Z = MY_setdiff(X,Y)
if ~isempty(X)&&~isempty(Y)
check = false(1, max(max(X), max(Y)));
check(X) = true;
check(Y) = false;
Z = X(check(X));
else
Z = X;
end
Obviously, if you're confident your inputs will make sense you can get rid of the if stuff.
tic;
size=50000;
a=round(100*rand(size,1));
b=round(100*rand(size,1));
intersect(a,b);
setdiff(a,b);
toc;
% Elapsed time is 0.028182 seconds.
tic;
size=50000;
a=round(100*rand(size,1));
b=round(100*rand(size,1));
MY_intersect(1+a,1+b)-1;
MY_setdiff(1+a,1+b)-1;
toc;
% Elapsed time is 0.016935 seconds.
The computation times vary a lot though, but the 2nd block is always at least around 30% faster. You can see how it plays out in your code and let us know.
  3 commentaires
Jonathan Epperl
Jonathan Epperl le 18 Août 2014
That's a good point, I never realized that.
Chinmaya KA
Chinmaya KA le 9 Sep 2020
Hi Jonathan, how can we intersect multiple arrays with positive integers using your code?

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Sean de Wolski
Sean de Wolski le 15 Nov 2012
Look at ismember and ismembc (two output form).
You will have to implement the and/or/xor logic yourself, but these should quickly give you the indices you need to do so.
  1 commentaire
Ethan Kyzivat
Ethan Kyzivat le 9 Mai 2018
I found that ismember also calls unique(), so may not be much faster...

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