Output standard deviation and Mean

When i run my programme, how do i only output the fprintf values?

function [VSD,M] = mean_stdev(A)
    A=input('N numbers:')
    
    % This function calculates the mean and standard deviation without
    %   using in-built functions

som=0;
for i=1:length(A)
  som=som+A(i);
end

M=som/length(A) %the mean
fprintf('Mean is: %f\n', M)
moy=0;
for i=1:length(A)
    moy = (A(i)- M)^2;
    moy = (moy)/length(A);
end

VSD=sqrt(moy/length(A)) %Varaince
fprintf('stadard dev: %f\n',VSD)
end

The output

>> mean_stdev
N numbers:
[5 6 7 8]

A =

     5     6     7     8


M =

    6.5000

Mean is: 6.500000

VSD =

    0.3750

stadard dev: 0.375000

ans =

    0.3750

>> 

[August Hardie]

Add semicolons at the end of statements to suppress output.

A=input('N numbers:') ;
M=som/length(A) ; %the mean
VSD=sqrt(moy/length(A)) ; %Varaince

Lastly, to suppress the 'ans' output, add a semicolon to the end of your function ' mean_stdev( ) ; ' whenever calling it.

Answer 1

[David Hill]

Function call. I would do the printing after the function call returns. But, this should work for you.

[s,m]=mean_stdev();

After function call returns.

A=input('N numbers:');
[VSD,M]=mean_stdev(A);
fprintf('Mean is: %f\n', M);
fprintf('stadard dev: %f\n',VSD);


function [VSD,M] = mean_stdev(A)
som=0;
for i=1:length(A)
  som=som+A(i);
end
M=som/length(A); %the mean
moy=0;
for i=1:length(A)
    moy = (A(i)- M)^2;
    moy = (moy)/length(A);
end
VSD=sqrt(moy/length(A)); %Varaince
end

[Christopher Clarke]

Thank you