Euler's Method

11 vues (au cours des 30 derniers jours)
Edinson Manga
Edinson Manga le 7 Juin 2020
Commenté : darova le 12 Juin 2020
Hi!
Model of an epidemic: We will now describe a mathematical model for the spread of an epidemic.
Suppose we have a community of L people that initially contains P infected people and Q uninfected people. Let y (t) be the number of people infected at one time t. If the disease is not very serious, like the common cold, everyone continues to be active and the epidemic spreads.
Since there are P Q possible contacts between people from one group to another, the rate of change of y (t) is proportional to
P Q, so the problem can be modeled using the initial value problem
(a) Taking L = 25000, k = 0.00003 and h = 0.2, with the initial condition y0 = 250, use
Euler's method to approximate the solution of the P.V.I. in the interval [0, 60].
(b) Draw the graph of the approximate solution in part (a).
(c) Estimate the average number of people infected by calculating the arithmetic mean
of section (a).
  1 commentaire
Edinson Manga
Edinson Manga le 7 Juin 2020
H = [0.2];
Y_euler = cell(1,numel(H));
for k=1:numel(H)
h = H(k);
x = 0:h:60;
y = zeros(1, numel(x));
y(1) = 250;
n = numel(y);
for i=1:n-1
f = ((0.00003*y(i))*(25000-y(i)));
y(i+1) = y(i) + h * f;
end
Y_euler{k} = [x; y].';
end
syms Y(X)
eq = diff(Y) == (0.00003*Y)*(25000-Y);
ic = Y(0) == 250;
sol = dsolve(eq, ic);
y_sol = double(subs(sol, X, x));
hold on
plot(x, y_sol, 'r', 'DisplayName', 'true solution');
for k=1:numel(H)
plot(Y_euler{k}(:,1), Y_euler{k}(:,2), 'b--', 'DisplayName', ['Euler method h=' num2str(H(k), '%.3f')]);
end
legend
This is my attempt, but I still can't find a way to find the arithmetic mean.

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Réponses (1)

Alan Stevens
Alan Stevens le 7 Juin 2020
Modifié(e) : Alan Stevens le 7 Juin 2020
Here's a rather simpler way to do what you want:
% EulerEpidemic.m
% Data
L = 25000; k = 0.00003; h = 0.2;
y0 = 250; tend = 60;
n = tend/h;
% Initial conditions
y(1) = y0;
t(1) = 0;
% Euler
for i = 2:n+1
f = k*y(i-1)*(L - y(i-1));
y(i) = y(i-1) + h*f;
t(i) = (i-1)*h;
end
Average = round(mean(y),0);
% True
i = 1:n+1;
y_true(i) = L./( 1 - (1-L/y0)*exp(-k*L.*t(i)) );
% Graph
plot(t,y,'--',t,y_true,'r'),grid
xlabel('time'),ylabel('infected')
legend('Euler','True')
text(20,L/2,['Average = ', num2str(Average)])
  4 commentaires
Alan Stevens
Alan Stevens le 8 Juin 2020
Modifié(e) : Alan Stevens le 8 Juin 2020
What error? It works perfectly for me! Describe the error message that you get.
darova
darova le 12 Juin 2020
i changed this line
Average = round(mean(y));
and it works ok for me too

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