Answered

must return a column vector

Do you want something like this sp=-0.5:0.5:14.5; for i = 1:length(sp) [t,y(:,i)]=ode45(@(t,y) phy_ode_1(t,y,sp(i)),0:0.5:1...

must return a column vector

Do you want something like this sp=-0.5:0.5:14.5; for i = 1:length(sp) [t,y(:,i)]=ode45(@(t,y) phy_ode_1(t,y,sp(i)),0:0.5:1...

environ 6 heures ago | 1

Answered

Finding a range of data greater than 0.1

There must be a neater way, but the following might help: X = [ 0.02 0.17 0.32 0.28 0.04 -0.07 -0.01 -0.19 -0.45 ....

Finding a range of data greater than 0.1

There must be a neater way, but the following might help: X = [ 0.02 0.17 0.32 0.28 0.04 -0.07 -0.01 -0.19 -0.45 ....

environ 7 heures ago | 0

| accepted

Answered

How to use ode45 with a time dependant second order differential equation

Turn your second order equation into two simultaneous first order equations.

How to use ode45 with a time dependant second order differential equation

Turn your second order equation into two simultaneous first order equations.

1 jour ago | 0

Answered

how can i solve this problem with rk4 method?

If m=20, k=20, c=40 then function f should be f = -(c/m)*v - k/m f=@(t,x,v) -2*v -x; %dvdt

how can i solve this problem with rk4 method?

If m=20, k=20, c=40 then function f should be f = -(c/m)*v - k/m f=@(t,x,v) -2*v -x; %dvdt

2 jours ago | 0

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Answered

How to solve a function with different ranges

Try C_ox = [16;15;7.5;2;7.5;15;15]; C_ox(C_ox<=15)=C_ox(C_ox<=15)/15; C_ox(C_ox>15)=1

How to solve a function with different ranges

Try C_ox = [16;15;7.5;2;7.5;15;15]; C_ox(C_ox<=15)=C_ox(C_ox<=15)/15; C_ox(C_ox>15)=1

3 jours ago | 0

Answered

how can i solve second order ODE with RK-4 without using a built in function in matlab?

This K11 = RK4(t(i), y1(:, i)); should be | K11 = RK4(t(i), y(:, i)); and this f12 = -3*y(1)+30*t+10; ...

how can i solve second order ODE with RK-4 without using a built in function in matlab?

This K11 = RK4(t(i), y1(:, i)); should be | K11 = RK4(t(i), y(:, i)); and this f12 = -3*y(1)+30*t+10; ...

4 jours ago | 0

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Answered

How to design the membership function in matlab?

How about the following for rule 3 (I'll leave you to invert for rule 4). x = [-180 -90 -89.001 89.001 90 180]; y = (x+180)/90...

How to design the membership function in matlab?

How about the following for rule 3 (I'll leave you to invert for rule 4). x = [-180 -90 -89.001 89.001 90 180]; y = (x+180)/90...

7 jours ago | 0

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Answered

Help for plotting graph. Can someone help me?

In your while loop you don't update either nErrorsBitsW or nErrorsBitsInf so they always stay at 0, and never reach minNbits.

Help for plotting graph. Can someone help me?

In your while loop you don't update either nErrorsBitsW or nErrorsBitsInf so they always stay at 0, and never reach minNbits.

7 jours ago | 0

Answered

how I can insert these specific colours into my figures

Do you mean something like this? newcolors = [0 0.4470 0.7410; 0.8500 0.3250 0.0980; 0.9290 0.6940 0.1250...

how I can insert these specific colours into my figures

Do you mean something like this? newcolors = [0 0.4470 0.7410; 0.8500 0.3250 0.0980; 0.9290 0.6940 0.1250...

9 jours ago | 1

Answered

Transpose x from a row vector to a column vector using the transpose operator. The program is prompting the x does not have correct values. the code i have entered is below

You probably meant x = [1:5]; % ie the ; is after the ] However, it seems to work ok for me as you wrote it!

Transpose x from a row vector to a column vector using the transpose operator. The program is prompting the x does not have correct values. the code i have entered is below

You probably meant x = [1:5]; % ie the ; is after the ] However, it seems to work ok for me as you wrote it!

9 jours ago | 0

Answered

Replace a entry of a table of Bisection Method for a specific term

Try using NaN or [ ];

Replace a entry of a table of Bisection Method for a specific term

Try using NaN or [ ];

9 jours ago | 0

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Answered

Plotting the intersection of a composition function

Do you mean something like this? Sfn = @(x) (x+1/4).*(x<=1/2) + (x+3/4).*(x>1/2); x = linspace(0,1,100); n=10; S = zeros(n,n...

Plotting the intersection of a composition function

Do you mean something like this? Sfn = @(x) (x+1/4).*(x<=1/2) + (x+3/4).*(x>1/2); x = linspace(0,1,100); n=10; S = zeros(n,n...

19 jours ago | 0

Answered

Sun Synchronous with For Loop

When I run the program you've listed above it produces the graph you show!

Sun Synchronous with For Loop

When I run the program you've listed above it produces the graph you show!

19 jours ago | 0

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Answered

Integration of a function with variable parameter

Do you mean something like this? H = @(tau, lam, tt) lam./exp(tt-tau); T=50; step=1000; h=T/step; t=0:h:T; lambda = rand(1...

Integration of a function with variable parameter

Do you mean something like this? H = @(tau, lam, tt) lam./exp(tt-tau); T=50; step=1000; h=T/step; t=0:h:T; lambda = rand(1...

20 jours ago | 0

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Answered

How to get sinusodial behaviour from 2nd order ode using function handle?

You coud try implementing the function along these lines (obviously, you will need to use your own values for alpha etc): alpha...

How to get sinusodial behaviour from 2nd order ode using function handle?

You coud try implementing the function along these lines (obviously, you will need to use your own values for alpha etc): alpha...

21 jours ago | 0

Answered

How to find absolute maximum value of (x*(x-.25)*(x-.5)*(x-1))

You could just do something like gx = @(x) ((x.^4) -(1.75*x.^3)+(0.875*x.^2)-(0.125*x)); X = roots([4, -5.25, 1.75, -0.125]); ...

How to find absolute maximum value of (x*(x-.25)*(x-.5)*(x-1))

You could just do something like gx = @(x) ((x.^4) -(1.75*x.^3)+(0.875*x.^2)-(0.125*x)); X = roots([4, -5.25, 1.75, -0.125]); ...

23 jours ago | 0

Answered

I want to see N,M first and then K,M in the same legend. I can see only N,M like the attached picture.

Do you mean like this? N = [10 20 30 40 50]; M = [1 2 3 4 5]; K=[1 3 5 6 7]; x = linspace(0, 1, 17); legendString = "N = " ...

I want to see N,M first and then K,M in the same legend. I can see only N,M like the attached picture.

Do you mean like this? N = [10 20 30 40 50]; M = [1 2 3 4 5]; K=[1 3 5 6 7]; x = linspace(0, 1, 17); legendString = "N = " ...

23 jours ago | 0

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Answered

How to take integral with for loop?

Add the command I = sum(final); after the loop.

How to take integral with for loop?

Add the command I = sum(final); after the loop.

24 jours ago | 0

| accepted

Answered

Solving queue problem iterating through array

Try Lock19(Lock19~=-5)=0; Lock19(Lock19==-5)=3;

Solving queue problem iterating through array

Try Lock19(Lock19~=-5)=0; Lock19(Lock19==-5)=3;

24 jours ago | 0

Answered

Sum of even numbers

Like so s = test(6); disp(s) function s = test(n) if n <= 0 %for n<= 0 the result would be 0 s = 0; els...

Sum of even numbers

Like so s = test(6); disp(s) function s = test(n) if n <= 0 %for n<= 0 the result would be 0 s = 0; els...

environ un mois ago | 0

Answered

Stopping ode45 when encountering errors and retrieving results

The following makes your example work. However, I suspect your real problem is more complicated. If so, you should upload it. ...

Stopping ode45 when encountering errors and retrieving results

The following makes your example work. However, I suspect your real problem is more complicated. If so, you should upload it. ...

environ un mois ago | 0

Answered

After comma precision tracking for if statement

Here's one possibility a=85.0093792283283; b=85.0093791964294; a = floor(a*10^3); b = floor(b*10^3); if a==b disp('n...

After comma precision tracking for if statement

Here's one possibility a=85.0093792283283; b=85.0093791964294; a = floor(a*10^3); b = floor(b*10^3); if a==b disp('n...

environ un mois ago | 0

Answered

help me solve this if statement

Remove the ] in the top line! Then number = randi([0,9]) evens = [2,4,6,8]; odds = [1,3,5,7,9]; if ismember(number,evens) ...

help me solve this if statement

Remove the ] in the top line! Then number = randi([0,9]) evens = [2,4,6,8]; odds = [1,3,5,7,9]; if ismember(number,evens) ...

environ un mois ago | 0

Answered

Error: ode45 Must return a column vector?

Like this? % the total time domain response % System parameters k3 = 15; k1 = 10.0; k2 = 10.0; m1 = 2.0; m2 = 6.0; L = 1.0;...

Error: ode45 Must return a column vector?

Like this? % the total time domain response % System parameters k3 = 15; k1 = 10.0; k2 = 10.0; m1 = 2.0; m2 = 6.0; L = 1.0;...

environ un mois ago | 1

| accepted

Answered

How to solve following BVP ODE?

Weird ODE and initial boundary condition! You can solve for small values of x using the following (where y(x=0) was chosen by t...

How to solve following BVP ODE?

Weird ODE and initial boundary condition! You can solve for small values of x using the following (where y(x=0) was chosen by t...

environ un mois ago | 1

| accepted

Answered

Array indexes must be positive integers or logical values.

Looks like you are using SUM when you want sum. Change to: SUM= E1*sum(V(3:IOUT+1,JOUT+2)).... Also, in line 59, you should h...

Array indexes must be positive integers or logical values.

Looks like you are using SUM when you want sum. Change to: SUM= E1*sum(V(3:IOUT+1,JOUT+2)).... Also, in line 59, you should h...

environ un mois ago | 1

| accepted

Answered

How to get real solutions of a "system of nonlinear equations"?

If you are willing to do the differentiation by hand then the following works % L = 2*x^2 -2*x*y+y^3 + lambda*(x^2 + y^2 -4); ...

How to get real solutions of a "system of nonlinear equations"?

If you are willing to do the differentiation by hand then the following works % L = 2*x^2 -2*x*y+y^3 + lambda*(x^2 + y^2 -4); ...

environ un mois ago | 0

Answered

Calling Euler Method to solve Shooting Method

You need to express your 2nd order ode as two 1st order odes y``(x) + 5y`(x) + 4y(x) = 1 v = dy/dx dv/dx = y``(x) So you h...

Calling Euler Method to solve Shooting Method

You need to express your 2nd order ode as two 1st order odes y``(x) + 5y`(x) + 4y(x) = 1 v = dy/dx dv/dx = y``(x) So you h...

environ un mois ago | 0

| accepted

Answered

solving Diffrential equation one parameter related to another one

Like this? %% Input Parameters Rs = 200; Rr = 180; Phi = 180; t = 0:1:359; e = Rs - Rr; %% Calculation B = @(t) e*co...

solving Diffrential equation one parameter related to another one

Like this? %% Input Parameters Rs = 200; Rr = 180; Phi = 180; t = 0:1:359; e = Rs - Rr; %% Calculation B = @(t) e*co...

environ un mois ago | 0