How can I reduce the time complexity of this matlab code.. Its taking lot of time to execute when an image is fed as input.

2 vues (au cours des 30 derniers jours)
cnt1=0; cnt2=0; cnt3=0; cnt4=0; cnt5=0; cnt6=0; cnt7=0; cnt8=0;
p = 1;
row = 1;
while p<(size(Theta_deg_img,1))
q = 1;
while q<(size(Theta_deg_img,2))
for i=p:p+8
for j=q:q+8
if Theta_deg_img(i,j)>=-180 && Theta_deg_img(i,j)<=-135
cnt1 = cnt1+1;
elseif Theta_deg_img(i,j)>=-134 && Theta_deg_img(i,j)<=-90
cnt2 = cnt2 + 1;
elseif Theta_deg_img(i,j)>=-89 && Theta_deg_img(i,j)<=-45
cnt3 = cnt3 + 1;
elseif Theta_deg_img(i,j)>=-44 && Theta_deg_img(i,j)<=0
cnt4 = cnt4 + 1;
elseif Theta_deg_img(i,j)>=1 && Theta_deg_img(i,j)<=45
cnt5 = cnt5 + 1;
elseif Theta_deg_img(i,j)>=46 && Theta_deg_img(i,j)<=90
cnt6 = cnt6 + 1;
elseif Theta_deg_img(i,j)>=91 && Theta_deg_img(i,j)<=135
cnt7 = cnt7 + 1;
else
cnt8 = cnt8 + 1;
end
eval([fsrc '(row,1) = cnt1;']);
eval([fsrc '(row,2) = cnt2;']);
eval([fsrc '(row,3) = cnt3;']);
eval([fsrc '(row,4) = cnt4;']);
eval([fsrc '(row,5) = cnt5;']);
eval([fsrc '(row,6) = cnt6;']);
eval([fsrc '(row,7) = cnt7;']);
eval([fsrc '(row,8) = cnt8;']);
end
end
q = q + 9; row = row+1;
cnt1=0; cnt2=0; cnt3=0; cnt4=0; cnt5=0; cnt6=0; cnt7=0; cnt8=0;
end
p = p + 9;
end

Réponse acceptée

Harshit
Harshit le 23 Nov 2012
Vectorize your code. Example you don't need inner loops you can use sum to get the value of counts. In the outer two loops you are calculating size again and again. Store it in a variable.
  5 commentaires
Harshit
Harshit le 26 Nov 2012
Yes it will just think about it. Whenver the condn is true 1 will be generated in the matrix and otherwise 0. sum will give the no of 1.
.. Vamshi
.. Vamshi le 26 Nov 2012
I followed your suggestion.. the counts have to be stored for every iteration.. but here am unable to do..

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Akiva Gordon
Akiva Gordon le 23 Nov 2012

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