how can i calculate in matlab

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Neha Jaiswal
Neha Jaiswal le 11 Juin 2020
we borrowed $1000 at a 10% anual intrests rate. if we do not makre a payment for 2 years, and assuming there is no penalty for non payment, how much do we owe now?
  4 commentaires
Alfred Jones Arokiaraj
Alfred Jones Arokiaraj le 8 Oct 2021
wrong answer . try in CI. answer will be 1.2100e+03
Walter Roberson
Walter Roberson le 8 Oct 2021
At the MATLAB command prompt give the command
format long g
now ask to display the result again.

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Réponse acceptée

Atsushi Ueno
Atsushi Ueno le 11 Juin 2020
simple interest:
1000 + (1000 * 0.1) * 2
compound interest:
1000 + 1000 * 0.1 + (1000 + 1000 * 0.1) * 0.1
or
1000 * (1 + 0.1) ^ 2
as function
simple interest:
function current = simple_interest(debt, rate, period)
current = debt + (debt * rate) * period;
end
compound interest:
function current = compound_interest(debt, rate, period)
current = debt * (1 + rate) ^ period;
end
  3 commentaires
Atsushi Ueno
Atsushi Ueno le 11 Juin 2020
I'm sorry. I'll be more careful from now on.
Neha Jaiswal
Neha Jaiswal le 11 Juin 2020
thank you. it was first question so i was unable to understand.

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Plus de réponses (4)

Roopesh R Peter
Roopesh R Peter le 3 Août 2020
Modifié(e) : Rik le 3 Août 2020
Compound the interest once a year:
debt = 1000 + 1000 * 0.1 + (1000 + 1000 * 0.1) * 0.1
  1 commentaire
Rik
Rik le 3 Août 2020
(I moved the flag content to the answer body, since it shouldn't have been a tag)

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Shivani Dubey
Shivani Dubey le 17 Sep 2020
p = 1000
r = 10/100
n= 1
t = 2
S =(1.1)^2
debt = p* S
  1 commentaire
ahmed hammad
ahmed hammad le 1 Sep 2021
thanks i had a tried a different methode and it has the same result but it was rejected when i submitted it to COURSERA but when i tried to you know simplify it like you did it worked
Thanks.

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Medical Imaging
Medical Imaging le 23 Sep 2020
The problem is simple and related to finance,
Borrowed_money = 1000;
Interest_rate = 10/100;
Delay_year = 2;
debt = Borrowed_money*(1+Interest_rate)^Delay_year

Jayashri Patil
Jayashri Patil le 13 Sep 2021
clear "all"
clc
n=input('enter the number of different pipe size: ');
rho=input('enter the value of density: ');
Mu=input('enter the value of viscocity: ');
Q=input('enter the flowrate: ');
e=input('enter the epsilon: ');
g=input('enter the accleration gravity: ');
for i=1:n
D(i)=input('enter the diameter of pipe: ','s');
L=input('enter the length of pipe: ','s');
KL(i)=input('enter the value of bends: ','s');
end
for i=1:n
A(i)=pi*D(i)*D(i)/4;
v(i)=Q/A(i);
ReynoldsNumber(i)=rho*v(i)*D(i)/Mu;
if ReynoldsNumber(i) <2300
f(i)=64/ReynoldsNumber(i);
elseif ReynoldsNumber(i) >4000
c=@(f)(l/sqrt(f(i)))+(2*log10*(e/D(i)*3.7+2.51/ReynoldsNumber(i)*sqrt(f(i))));
f(i)=fzero(c,[0.01,0.05]);
end
deltap(i)=(f(i)*(L(i)/D(i))*((rho*v(i)*v(i))/2)/1000); % pressure drop in kpa
HL(i)=(f(i)*(L(i)/D(i))+KL(i)*v(i)*v(i)/2*g); % head loss in m
end
  4 commentaires
Jayashri Patil
Jayashri Patil le 13 Sep 2021
how to take nth number of inputs from user
Rik
Rik le 13 Sep 2021
You already posted a very similar question. Why not post a comment there with a follow-up question?

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