How to create a matrix from multiples of submatrice?

4 vues (au cours des 30 derniers jours)
Timon Viola
Timon Viola le 11 Juin 2020
Modifié(e) : madhan ravi le 11 Juin 2020
I would like to find a smarter way of building a larger matrix from vectors. The following code works fine:
rv = [1 2 3 4];
alpha =[0.0140;
0.0100;
0.0100;
0.0100];
c = [];
for i = 1:4
c = [c; diag(alpha).*rv(i)];
end
>> c =
0.0140 0 0 0
0 0.0100 0 0
0 0 0.0100 0
0 0 0 0.0100
0.0280 0 0 0
0 0.0200 0 0
0 0 0.0200 0
0 0 0 0.0200
0.0420 0 0 0
0 0.0300 0 0
0 0 0.0300 0
0 0 0 0.0300
0.0560 0 0 0
0 0.0400 0 0
0 0 0.0400 0
0 0 0 0.0400
Essentially I build a submatrix from a vector. Then I multiple the diagonal submatrix with each element of a vector. Then I concatenate these vertically.
Is there a computationally more efficient way of doing this?
Thanks!

Réponse acceptée

madhan ravi
madhan ravi le 11 Juin 2020
Modifié(e) : madhan ravi le 11 Juin 2020
Z = reshape(rv,1,1,[]) .* diag(Alpha);
Wanted = reshape(Z,numel(rv),[]).'
  2 commentaires
Michael Soskind
Michael Soskind le 11 Juin 2020
Even more confusing but with no tansposes and in one line:
repmat(diag(alpha),4,1).*reshape(repmat(rv, 4,4),[],4)
madhan ravi
madhan ravi le 11 Juin 2020
Modifié(e) : madhan ravi le 11 Juin 2020
" and in one line"
Wanted = reshape(reshape(rv,1,1,[]) .* ...
diag(Alpha),numel(rv),[]).'
"Even more confusing"
Why?
N = 1e6;
tic
for k = 1:N
Z = reshape(rv,1,1,[]) .* diag(Alpha);
Wanted = reshape(Z,numel(rv),[]).';
end
% Elapsed time is 4.847994 seconds.
toc
tic
for k = 1:N
repmat(diag(alpha),4,1) .* reshape(repmat(rv, 4,4),[],4);
end
toc
% Elapsed time is 5.865444 seconds.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrices and Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by