matlab code for musical note recognition based on frequency
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i am working on a project to identify the musical note based on frequencies using window methods i need help to write the code and understanding it . ihave a code but its to advanced to understand......
clear;
clc;
close all;
% Note Recognition
%% Note Initialization
mainNames = char('C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B');
names = char('A0', 'A#0' ,'B0');
A0 = 27.5;
ind = 4;
for i = 0:87
data(i+1) = A0 * (2^(1/12))^i;
if i>2
a = [mainNames( rem((ind - 4), 12)+1,:) num2str(fix((ind - 4)/12)+1)];
names = char(names, a);
ind = ind + 1;
end
end
% Band Initialization
bands(1) = 20;
for i = 1:87
bands(i+1) = +7+(data(i) + data(i+1))/2;
end
bands(89) = 4500;
%%
fileName = 'c.wav'; % File name
[y, Fs] = audioread(fileName); % Read audio file
y = (y(:,1) + y(:,2))*4; % Decrease 2 channels to 1
%y = (y(:,1));
y(1:2:end) = 0; %from big vector take only odd index values % Do decimation(decreace the no of samples)
frameLength = 4410*2; % 2 Güzel oldu
endPart = frameLength*ceil(length(y)/frameLength); % complete the last frame %ceil is to round off to nearest integer
y(length(y)+1 : endPart) = 0;
f = linspace(1,Fs,frameLength); %creates linearly spaced vector
%%
harmonics = 0;
for i = 1:round(length(y)/frameLength) % For each frame
% Divide audio into frames
frames(i, 1:frameLength) = y( (frameLength*(i-1)+1):(frameLength*i) )';
frame = y( (frameLength*(i-1)+1):(frameLength*i) )';
frame = frame .* hamming(length(frame))'; % Hamming Window
fframe = abs(fft(frame)); % FFT
fp = sum(fframe);
p = sum(abs(frame));
b = true;
if(p < 200 || fp < 1000) % Put a threshold for processing
b = false;
end
% Bands
for i=1:88
freqBand(i) = mean(fframe( round(bands(i)/(Fs/frameLength) ):round(bands(i+1)/(Fs/frameLength))))^2;
end
% Plotting
subplot(3,1,1)
stem(freqBand)
subplot(3,1,2)
plot(fframe)
xlim([0,500])
subplot(3,1,3)
plot(fframe)
ylim([-1 1])
hold off
pause(0.1)
sound(fframe,Fs)
% Desicion
m = find(freqBand == max(freqBand(:)));
if(b) disp(names(m,:)); % Print the result
else disp('.'); end
if(b)
index = 1;
for i = 1:88
if(freqBand(i) > 2000)
harmonics(index) = i;
index = index+1;
end
end
end
end
this is the code.....
1 commentaire
Paavan Kumar Dornadula
le 20 Juil 2020
how to verify is above code is correct or not?
Réponse acceptée
Plus de réponses (1)
Geetesh Mokhare
le 29 Mar 2021
0 votes
endPart = frameLength*ceil(length(y)/frameLength
WHAT IS THE MEANING OF THIS?
2 commentaires
varun taliparambe vitel
le 29 Mar 2021
Geetesh Mokhare
le 29 Mar 2021
One more help Can you tell me the application of this code in 5-6 lines ? Please request
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