Subtract mean from each table by columns
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wbadry
le 14 Juin 2020
Commenté : Image Analyst
le 22 Juin 2020
Hello,
Assume we have the following table
t = array2table([rand(10,1),rand(10,1),rand(10,1)],'VariableNames',{'feat_1', 'feat_2','feat_3'});
t =
10×3 table
feat_1 feat_2 feat_3
________ ________ _________
0.12991 0.60198 0.82582
0.56882 0.26297 0.53834
0.46939 0.65408 0.99613
0.011902 0.68921 0.078176
0.33712 0.74815 0.44268
0.16218 0.45054 0.10665
0.79428 0.083821 0.9619
0.31122 0.22898 0.0046342
0.52853 0.91334 0.77491
0.16565 0.15238 0.8173
I can get the mean and standard deviation for each solumn using
meanArray = mean(table2array(t,1));
stdArray = std(table2array(t,1));
meanArray =
0.3479 0.4785 0.5547
stdArray =
0.2415 0.2836 0.3793
Is there any vector way to caclulate (element - mean / std) on every element in table without loop and keep the table? Thanks
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Image Analyst
le 14 Juin 2020
Modifié(e) : Image Analyst
le 14 Juin 2020
Try this:
t = array2table([rand(10,1),rand(10,1),rand(10,1)],'VariableNames',{'feat_1', 'feat_2','feat_3'})
m = table2array(t);
meanArray = mean(m)
stdArray = std(m)
z = (m - meanArray) ./ stdArray % a matrix
zt = array2table(z, 'VariableNames',{'feat_1', 'feat_2','feat_3'}) % a table
Plus de réponses (1)
wbadry
le 22 Juin 2020
1 commentaire
Image Analyst
le 22 Juin 2020
Yeah, you can do it that way if you want. I always find their *xfun() functions very cryptic and confusing than the regular math symbols. Plus you always have to find or figure out what the operations are. I mean, who would know, off the top of their head, that if you want to divide something you use @rdivide instead of the slash symbol /, or @minus instead of -. And it gets even more confusing for other operations.
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