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Why do I get error incorrect use of '=' operator?

9 vues (au cours des 30 derniers jours)
현우 이
현우 이 le 19 Juin 2020
Commenté : 현우 이 le 19 Juin 2020
I made the drunk man simulation. But if I run this, I get the error message Error: Incorrect use of '=' operator. To assign a value to a variable, use '='. To compare values for equality, use '=='.
and if I change = to <=, I get the error message
while (s<10 && s >-10 && i<100)
Error: Illegal use of reserved keyword "while".
Why does this happen and how can I fix it? Thanks a lot in advance.
This is my code.
alive = 0
success = 0
dead = 0
p = 0.5
for n=1:1000
{
i = 0
s = 0
while (s<10 && s >-10 && i<100)
x = rbinom(1, 1, p);
if(x == 1)
s = s-1;
else
s = s+1;
i = i+1;
end
if(s == 10)
success = success + 1;
end
if(s == -10)
dead = dead + 1;
end
end
if(s<10 &&s > -10)
alive = alive +1;
end
barplot(c(success, dead, alive))

Réponse acceptée

Nipun Agarwal
Nipun Agarwal le 19 Juin 2020
Hey,
The problem comes in because of curly braces after the for loop. MATLAB syntax never allows curly braces after the for loop. I have updated the code of yours and indented it properly for you to have a better standing.
alive = 0;
success = 0;
dead = 0;
p = 0.5;
for n=1:1000
i = 0;
s = 0;
while (s<10 && s >-10 && i<100)
x = 1;
if(x == 1)
s = s-1;
else
s = s+1;
i = i+1;
end
end
if(s == 10)
success = success + 1;
end
if(s == -10)
dead = dead + 1;
end
if(s<10 &&s > -10)
alive = alive +1;
end
end
barplot(c(success, dead, alive))
  2 commentaires
Stephen23
Stephen23 le 19 Juin 2020
The MATLAB Editor's default indentation rules give this even clearer version:
alive = 0;
success = 0;
dead = 0;
p = 0.5;
for n=1:1000
i = 0;
s = 0;
while (s<10 && s >-10 && i<100)
x = 1;
if(x == 1)
s = s-1;
else
s = s+1;
i = i+1;
end
end
if(s == 10)
success = success + 1;
end
if(s == -10)
dead = dead + 1;
end
if(s<10 &&s > -10)
alive = alive +1;
end
end
barplot(c(success, dead, alive))
현우 이
현우 이 le 19 Juin 2020
Thank you!

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