How to solve an equation in a certan interval.
8 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Problem:
syms w; % variable, that define the y axis
lam = 4*pi()^2 % constant, that define the x axis
tan(w/2) == w/2 - (4/(lam))*(w/2)^3 % equation
That equation with that constant has many solutions. What I pretend is to resolve the equation (maybe with solve) for lam = 4*pi()^2, in a certain interval of y, in order to catch a specific solution. For example, I know that for that constant there is a solution of w/pi() = 2 in the interval w/pi()=[1.5 2.5], (y axis).
I was trying with this:
syms w;
lam=4.*pi().^2;
x = fsolve(@(w) tan(w/2) == w/2 - (4./(lam)).*(w/2).^3, [1.5*pi() 2.5*pi()]);
X=x/pi()
But is giving me some problems that I can´t resolve.
On Maple software the structure of the program is more or less the same, but it gives me the solutions that I want in specific intervals of y axis.
Matlab has to do it too or it doesn't?
Thanks to all.
0 commentaires
Réponse acceptée
Walter Roberson
le 2 Déc 2012
The function you provide to fsolve() needs to have a numeric result rather than a logical result. Convert your form A==B to (A)-(B) or (B)-(A)
4 commentaires
Walter Roberson
le 8 Déc 2012
No, fsolve() does not take an interval. When you provide multiple values for x0 it becomes an equation with multiple variables. fzero() is the one that takes an interval.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Calculus dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!