How to generate one random integer
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I need to generate one random integer.
I tried these codes:
X = randi(1)
X = rand(1)
However, it only gives random numbers between 0 and 1 (like 0.2567, 0.9432, etc.).
I am hoping to get a random number from negative infinity to positive infinity.
What function should I use to be able to generate one random integer?
Thanks in advance!
5 commentaires
David
le 28 Jan 2024
Interestingly and confusingly; X = randi(2), for example, returns either a 1 or a 2, but note that the integer test on the outcome is false; i.e., the outcome is not recognized as integer.
>> X = randi(2)
X = 1
>> Xint = isinteger(X)
Xint = logical 0
Where does the problem lie; i.e. in which function, the generator or the test?
Walter Roberson
le 28 Jan 2024
isinteger() tests for integer data type, not for integer value.
The isinteger() function tests the numeric class of the input; it doesn't test for mod(x,1) == 0.
x = randi(1000,1,1) % this is double
mod(x,1) % it's an integer
isinteger(x) % but it's not integer-class
isfloat(x) % it's floating-point instead
x = int16(x); % now it's integer-class
isinteger(x)
David
le 28 Jan 2024
Right, I agree that isinteger is testing that a value is a member of the "integer class", but if randi purports to produce pseudo-random integers, then shouldn't results me members of the interger class without explaicitly declaring that they are; i.e., without the need for the "int16" declaration. (I guess not, and I appreciate your response, but if a function says it is returning an integer, then in my book, it should actually return an integer that tests "true" for being a member of that class. That's why I think this is confusing.
Dyuman Joshi
le 28 Jan 2024
There's a difference between the integer as a data type and integer as a numerical entity.
The function randi() does return an integer, but, by default, it is of class double.
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Walter Roberson
le 3 Juil 2020
Modifié(e) : Walter Roberson
le 28 Jan 2024
The following generates integers natively.
typecast(randi([0 255],1,8,'uint8'),'int64')
The range is all possible integers between -2^63 and +2^63-1
infinity cannot be generated with this setup, as infinity is not part of the integer system.
To generate integers outside of the range indicated above, you need to switch to double(), but if you do that, you only have 53 bits of precision available, and all values outside the range +/- 2^53 are integers that are multiplied by a power of 2 -- you could not, for example, generate 2^53 + 17 . By 1E50, adjacent representable values are 2^114 apart. Is that what you want to deal with?
1 commentaire
Roxanne Esguerra
le 3 Juil 2020
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