file name extraction from load file

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Akhtar Rind
Akhtar Rind le 3 Juil 2020
Commenté : Akhtar Rind le 4 Juil 2020
I have load data file to extract data and plots.
A typical file name would be '01_02_20_Cu_1.csv' and I use this as
A1= readcell('01_02_20_Cu_1.csv');
How can I get file name "01_02_20_Cu_1" from load data file as text format?

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Kawin Kumaran
Kawin Kumaran le 3 Juil 2020
fileparts() function can be used to extract file name .
file = '01_02_20_Cu_1.csv';
[~,name,~] = fileparts(file)
The result will be :
name : '01_02_20_Cu_1'
Please refer the following documentation for more information .
  1 commentaire
Akhtar Rind
Akhtar Rind le 4 Juil 2020
Fantastic. It worked. Many thanks Kawin.

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