find the right condition for my script

Given the variables present in the .mat file, I need to find the values ​​of the rows of the "distance" matrix (also using only the first column of values) in correspondence of which I have

in == 1

and

veloc == 0

This is how i wrote my code but i think i was wrong because i can't get the right result

r=0.007*ones(28,1);
[latc, lonc] = scircle1(lat_ferm(:,1), long_ferm(:,1), r);


    
for l=1:28
     in = inpolygon(lat,lon,latc(:,l),lonc(:,l));
     veloc_ferm=veloc(in);
     idx=double(in(:,1));
     %METTERE CONDIZONE SULLA VELOCITA'PER INIDIVIDUARE OPPORTUNAMENTE IDX
     %E LA POSIZIONE DELLE FERMATE
         [r c] = find(veloc(:,1)==0);
         v = diff(r);
         [r1 c3] = find(v > 1);
         pos_fermateR2(:,1)=distanza(r(r1(in)));
     end
  

[madhan ravi]

Could you just illustrate with an example of 2x2 matrix and desired result?

[Angela Marino]

Yes, e.g. if I consider only the first column

in=[0 1 1 0 0 0 0 1 1 1 0]';
veloc=[0.213 0 0 1.32 1.34 1.33 1.20 0 0 0 1.34]';
distanza=[10 11 11 12 13 14 15 16 16 16 17]';

pos_fermateR2=[11 16]';

Answer 1

[madhan ravi]

 pos_fermateR2 = unique(distanza((in==1) & (veloc==0)))

[Angela Marino]

Thanks so much!

[Angela Marino]

But if I wanted to specify that I only want the value that corresponds to the first instant equal to zero how could I do it?

[madhan ravi]

 find(veloc == 0, 1, 'first')

[Angela Marino]

Sorry, I meant the value that corresponds to the first instant equal to zero, but for each sequence of zeros

[madhan ravi]

You maybe better off starting a new question.