Reading image in zig zag, and arrange the output matrix in ascending and descending issue

I am trying to image a figure and create G-code by reading the figure in zig-zag way. Thus, first I red the figure and dedect the edges and generate matrix for the edges.

The generated matrix like this:

AA =

[ 21 13

22 13

23 13

24 13

41 13

42 13

43 13

44 13

45 13

46 13

18 14

19 14

20 14

25 14

26 14

27 14

28 14

47 14

48 14

17 15

29 15

41 15

48 15

. . ], so on.

What I need to do to, arrange the first colume at coloume two value 13 by ascending way, and at second column value 14 by decending way and so on.

after that, I want to format these coordiantions in G-code format

How can I do this?

attached is an example for my code until and a figure sample

[Image Analyst]

Not sure I understand but perhaps you want sort() or sortrows().

[Islam Hassan]

Yes I want to sortrows,.

But as you can see the matrix has two column, the second column begin with 13 and this 13 value repeatred for number of rows. Thus, I need to sort the rows which has the same value 13 in scond column in ascending order, and the rows which has the next value after 13 in s cond column in decdening order.

For exampple:

AA = [ 5 13

7 13

6 13

4 14

5 14

8 14

5 16

8 16

7 16

9 16

3 20

6 20

8 20

9 20

. . ] so on

I need to generate the following format:

AA = [ 5 13

6 13

7 13

8 14

5 14

4 14

5 16

7 16

8 16

9 16

9 20

8 20

6 20

3 20

. . ] so on

Hope the example make my point clear.

Answer 1

[Stephen23]

>> A = [5,13;7,13;6,13;4,14;5,14;8,14;5,16;8,16;7,16;9,16;3,20;6,20;8,20;9,20]
A =
    5   13
    7   13
    6   13
    4   14
    5   14
    8   14
    5   16
    8   16
    7   16
    9   16
    3   20
    6   20
    8   20
    9   20
>> B = sortrows(A,[2,1]);
>> X = ~mod(cumsum([true;diff(B(:,2))~=0]),2);
>> B(X,:) = sortrows(B(X,:),[2,-1])
B =
    5   13
    6   13
    7   13
    8   14
    5   14
    4   14
    5   16
    7   16
    8   16
    9   16
    9   20
    8   20
    6   20
    3   20

[Islam Hassan]

Thanks alot, that works.

Answer 2

[Image Analyst]

I suggested sortrows() above, so did you actually try it? Did you do

AA = [ 5 13
	7  13
	6  13
	4  14
	5  14
	8  14
	5  16
	8  16
	7  16
	9  16
	3  20
	6  20
	8  20
	9  20 ]
sortedAA = sortrows(AA, [2, 1])

to get

sortedAA =

5 13

6 13

7 13

4 14

5 14

8 14

5 16

7 16

8 16

9 16

3 20

6 20

8 20

9 20

If not, why not? Doesn't that do what you said you wanted to do?

[Islam Hassan]

Thanks for your reply.

However, the soredAA you generated is not exactly what I want. Please check the following illustration

Hope the illustration clear my point. Thanks in advance