Info

This question is locked. Rouvrir pour modifier ou répondre.

handle character minus character

4 vues (au cours des 30 derniers jours)
Ancalagon8
Ancalagon8 le 10 Juil 2020
Locked: Rena Berman le 13 Jan 2025
I have two characters which contain '18:29:42.835' and '18:29:49.425'. How is it possible to subtrack t2-t1 so as to find duration?
  1 commentaire
Rena Berman
Rena Berman le 13 Jan 2025

(Answers Dev) Restored edit

Réponse acceptée

madhan ravi
madhan ravi le 10 Juil 2020
f = @(x) str2double(regexp(x,':','split'));
t1 = num2cell(f(t1)); % where t1 & 2 are your char arrays
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:})
  1 commentaire
madhan ravi
madhan ravi le 10 Juil 2020
f = @(x) str2double(regexp(x,'\D','split'));
t1 = num2cell(f(t1));
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:});
Wanted.Format = 'hh:mm:ss.SSSS'

Plus de réponses (1)

Walter Roberson
Walter Roberson le 10 Juil 2020
If you have a recent enough MATLAB version, pass the character vectors to duration() and then subtract one from the other.
If your MATLAB is a bit older, then you will need to split the vectors at the colons, then str2double() to get the individual components, and pass those to duration.
Or you could use sscanf() with a format of '%f:%f:%f' to get the numeric components and pass those to duration()

This question is locked.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by