assume z0 = x0 + y0 * i;
if abs(z-z0)=R
then abs(z-z0)-R describes a circle with center of z0 and radius of R;
how can we use matlab to draw it?

Réponses (2)

madhan ravi
madhan ravi le 13 Juil 2020

0 votes

By defining z as a function of x and y and using fplot()
doc fplot
Alan Stevens
Alan Stevens le 13 Juil 2020

0 votes

How about:
x0 = 1; y0 = 2;
z0 = x0 + y0*i;
R = abs(z0);
theta = 0:1/360:2*pi;
x = x0 + R*cos(theta); y = y0 + R*sin(theta);
plot(x,y)

2 commentaires

madhan ravi
madhan ravi le 13 Juil 2020
What about z?
Alan Stevens
Alan Stevens le 13 Juil 2020
Modifié(e) : Alan Stevens le 13 Juil 2020
Yes, z needs to be defined as well. I simply took it as zero here for simplicity (the main idea being the use of cos and sin theta).
Didn't think of fplot - a much better idea!

Connectez-vous pour commenter.

Catégories

En savoir plus sur Line Plots dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by