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Solve "Index exceeds the number of array elements (1)", "Vectors must be the same length." errors

1 vue (au cours des 30 derniers jours)
I'd like to solve those problems from under coding using A, B, and C relationships. If equation error can't be fixed, "B(i+1)=B(i)+((h.*q)/(k*T*E))*C(i)" can be used.
a = 0;
b = 1;
n = 110;
k = 8.61733*10^(-5);
T = 300 ;
q = 1.60218*10^(-19);
E = 8.8542*10^(-12)
x= linspace(a,b,n);
h= x(2)-x(1);
A = zeros(size(x));
B = zeros(size(x));
for i = 0:n-1
A(0)=3;
B(0)=1;
C(i)=2*x(i)+3;
A(i+1)=A(i)-h.*B(i)-(0.5.*h.^2*q.*C(i))./(k*T*E);
B(i+1)=B(i)+((h.*q)/(k*T*E))*0.5*(C(i)+C(i+1));%equation error
end
plot(transpose(x),A,'.')
  1 commentaire
Tanmay Das
Tanmay Das le 15 Juil 2020
Hi. Can you please try starting the index from 1 instead of 0 and go upto n in the for loop?

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Réponse acceptée

Walter Roberson
Walter Roberson le 15 Juil 2020
a = 0;
b = 1;
n = 110;
k = 8.61733*10^(-5);
T = 300 ;
q = 1.60218*10^(-19);
E = 8.8542*10^(-12)
x= linspace(a,b,n);
h= x(2)-x(1);
A = zeros(size(x));
B = zeros(size(x));
A(0+1)=3;
B(0+1)=1;
for i = 0:n-1
C(i+1)=2*x(i+1)+3;
A(i+1+1)=A(i+1)-h.*B(i+1)-(0.5.*h.^2*q.*C(i+1))./(k*T*E);
B(i+1+1)=B(i+1)+((h.*q)/(k*T*E))*0.5*(C(i+1)+C(i+1+1));
end
plot(transpose(x),A,'.')
  12 commentaires
sookyung Kang
sookyung Kang le 20 Juil 2020
Yes. And no. I need to figure out that C equation by comparing theoretical equation as I didn't put this code.
Walter Roberson
Walter Roberson le 20 Juil 2020
Which theoretical equation are you comparing to, and which result from your program are you comparing it to?
How do you know when you have reached and adequate solution?

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Plus de réponses (1)

Tanmay Das
Tanmay Das le 15 Juil 2020
Hi,
I have the understanding that you are facing trouble in indexing of arrays. Unlike C++ or Python, indexing starts from 1 in MATLAB. So if you write A(0), then it will throw error. The following code may be useful for your understanding:
a = 0;
b = 1;
n = 110;
k = 8.61733*10^(-5);
T = 300 ;
q = 1.60218*10^(-19);
E = 8.8542*10^(-12)
x= linspace(a,b,n);
h= x(2)-x(1);
A = zeros(size(x));
B = zeros(size(x));
A(1)=3;
B(1)=1;
C = 2*x + 3
for i = 1:n-1
A(i+1)=A(i)-h.*B(i)-(0.5.*h.^2*q.*C(i))./(k*T*E);
B(i+1)=B(i)+((h.*q)/(k*T*E))*0.5*(C(i)+C(i+1));%equation error
end
plot(transpose(x),A,'.')
Also please note that similar operations on each element of array can be done at once in MATLAB and do not require to run a loop like in case of C.
C = 2*x + 3
Hope that helps!
  1 commentaire
sookyung Kang
sookyung Kang le 16 Juil 2020
Modifié(e) : sookyung Kang le 16 Juil 2020
Thanks for your reply.
But no it is not correct. It doesn't reflect C value as I could see same graph.
I've followed Walter Roberson's coding. Now I'm in the situation to fix the ploting graph as loop structure and x length are different.

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