Hello I have the following code below. LoD shows 3 diffrent reference times. tim is the time vector. I wish to add tim to each of the LoDs to generate 3 different sets of times. The problem is that when i try to add tim to a LoD the values in tim with decimal places are truncated. eg 0.5 is truncated to 0 and 1.5 is truncated to 1 and so on. How could i suppress the truncation while using every value in tim. How can i output the results from this loop. Kindly advise
LoD = ['2006-01-10 18:20:12'; '2006-02-14 14:25:10'; '2006-03-17 11:13:14'];
tim = [0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4];
for x= 1:length(LoD)
newdates = datestr(addtodate(datenum(LoD(x,1:19)), length(tim), 'sec'));
end

 Réponse acceptée

Walter Roberson
Walter Roberson le 16 Juil 2020

0 votes

LoD = ['2006-01-10 18:20:12'; '2006-02-14 14:25:10'; '2006-03-17 11:13:14'];
tim = [0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4];
basetimes = datetime(LoD);
temp = arrayfun(@(T) T+seconds(tim), basetimes, 'uniform', 0);
newdates = vertcat(temp{:});

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