The Tag Field of labSendReceive() Function
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Jim Chung
le 18 Juil 2020
Réponse apportée : Walter Roberson
le 20 Juil 2020
Hello, the Forum!
The following code allows the dataReceived vector of each node has the same values in its nodeList. But my question is how to make use of the "tag". I wish to inform the neighboring agents, say j, that some data corresponds to Agent i. I did it this way: dataReceived = [dataReceived, labSendReceive(nodeList{labindex}(i),nodeList{labindex}(i),labindex, labindex)], but it turned out to be something like an infinite loop. Thank you!
nodeList{1} = [2,4];
nodeList{2}= [1,4];
nodeList{3} = 4;
nodeList{4} = [1,2,3];
parpool('local',4);
spmd
% mydata = magic(labindex);
dataReceived = [ ];
for i = 1:length(nodeList{labindex})
% labSend(labindex,nodeList{labindex}(i));
% dataReceived = [dataReceived, labReceive(nodeList{labindex}(i))];
dataReceived = [dataReceived, labSendReceive(nodeList{labindex}(i),nodeList{labindex}(i),labindex)];
end
end
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Réponse acceptée
Edric Ellis
le 20 Juil 2020
The function labSendReceive requires matched communication, so the receiver always knows which lab sent the data. In your example, the nodeList entries are arranged so that there is no communication mismatch - but this will probably be difficult to arrange in the general case. I'm not quite sure where your actual problem is because your code as written completes successfully. I would consider re-writing the labSendReceive loop so that each worker communicates with each other worker in turn, like this:
spmd
dataReceived = cell(1, numlabs);
for labOffset = 1:(numlabs-1)
sendTo = 1 + mod(labindex-1 + labOffset, numlabs);
recvFrom = 1 + mod(labindex-1 - labOffset, numlabs);
dataToSend = magic(labindex);
dataReceived{recvFrom} = labSendReceive(sendTo, recvFrom, dataToSend);
end
end
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Walter Roberson
le 20 Juil 2020
The tag parameter is mostly intended to permit priority queuing. Except rather than the standard priority according to numeric values, the receiving end can query for a particular value to handle those first
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