Effacer les filtres
Effacer les filtres

Concatenate cells: making column and row headers

3 vues (au cours des 30 derniers jours)
Mich le 17 Déc 2012
I have a column and a row like this:
col={'cat1'; 'cat2'; 'cat3'}
row={'mouse1' 'mouse2' 'mouse3'}
I would like to make these as column and row headers (eventually for a table) like this such that my table looks like this:
I've attempted to use cat such that:
but it results in an error the dimensions are not consistent..
Thank you so much for your help and please let me know if I am not clear.
  2 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 17 Déc 2012
Your image is invisible
Mich le 17 Déc 2012
Oh! that is weird, here is the link: http://imgur.com/y0wyb I'm sorry!

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Réponse acceptée

Pedro Villena
Pedro Villena le 17 Déc 2012
table(2:numel(row)+1) = row;
table(2:numel(col)+1,1) = col;
  1 commentaire
Mich le 17 Déc 2012
Modifié(e) : Mich le 17 Déc 2012
That's it! The way that gave me the exact result was:
Thank you so much!! And to all the helpers, you are awesome!

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Plus de réponses (2)

Honglei Chen
Honglei Chen le 17 Déc 2012
table(2:4) = row;
table(2:4,1) = col;
  2 commentaires
Mich le 17 Déc 2012
Unfortunately i get a dimension mismatch error as well. I tried the method under Azzi's comment because with my real dataset I would not know the if it actually ended on the 4th row. Perhaps I am looking for something more like:
But I get a dimension mismatch.. Thank you for your response!!
Honglei Chen
Honglei Chen le 17 Déc 2012
The code below works fine for me. If you get an error, you may need to make sure that your variable, table, is not defined previously with other dimensions. If that still didn't work out, please post your example with the error message.
>> col = {'a','b','c'}
col =
'a' 'b' 'c'
>> row = {'d','e','f'}
row =
'd' 'e' 'f'
>> table(2:numel(row)+1) = row
table =
[] 'd' 'e' 'f'
>> table(2:numel(col)+1,1) = col
table =
[] 'd' 'e' 'f'
'a' [] [] []
'b' [] [] []
'c' [] [] []

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Matt Fig
Matt Fig le 17 Déc 2012
Modifié(e) : Matt Fig le 17 Déc 2012
row={'cat1'; 'cat2'; 'cat3'};
col={'mouse1' 'mouse2' 'mouse3'};
t = uitable('Data',[],...
'Position',[20 20 360 100])


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