cycle for integrating vector sections

2 vues (au cours des 30 derniers jours)
Lev Mihailov
Lev Mihailov le 21 Juil 2020
Commenté : Alan Stevens le 21 Juil 2020
Hello! I have a vector that I need to integrate over the sections, the length of the section is 3
% now I use such a loop, but it gives me 900 answers, but should 300
for i=1:length(Fi)
x=Fi(i:i+2); % +2 I need to integrate sections (3 values ​​per section)
LayerDepstep(i)=trapz(x);
end
% x=900 % 300
% Fi vector 1:900 %

Réponses (1)

Alan Stevens
Alan Stevens le 21 Juil 2020
Perhaps you should have something like:
for i=1:4:length(Fi)-2
x=Fi(i:i+2); % +2 I need to integrate sections (3 values ​​per section)
LayerDepstep(floor(i/4)+1)=trapz(x);
end
  2 commentaires
Lev Mihailov
Lev Mihailov le 21 Juil 2020
i tested this method but it didn't help me
Alan Stevens
Alan Stevens le 21 Juil 2020
It does what you appeared to be asking for, i.e. reduces the number of sections by a factor of 3. What problem remains?

Connectez-vous pour commenter.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by