cycle for integrating vector sections
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello! I have a vector that I need to integrate over the sections, the length of the section is 3
% now I use such a loop, but it gives me 900 answers, but should 300
for i=1:length(Fi)
x=Fi(i:i+2); % +2 I need to integrate sections (3 values per section)
LayerDepstep(i)=trapz(x);
end
% x=900 % 300
% Fi vector 1:900 %
0 commentaires
Réponses (1)
Alan Stevens
le 21 Juil 2020
Perhaps you should have something like:
for i=1:4:length(Fi)-2
x=Fi(i:i+2); % +2 I need to integrate sections (3 values per section)
LayerDepstep(floor(i/4)+1)=trapz(x);
end
2 commentaires
Alan Stevens
le 21 Juil 2020
It does what you appeared to be asking for, i.e. reduces the number of sections by a factor of 3. What problem remains?
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!