will creating a variable map(i,j) = {array} (this is inside two for loops) create a variable that has i locations with unique locations j inside i?

1    for i = 100:100:500
2      A = load('data_i', 'gotcha');
3      B = load(data_i+100, 'gotcha');
4      gotcha1 = A.gotcha;
5      gotcha2 = B.gotcha;
6      length = size(unique(gotcha1)) - 1;
7      for j = 1:length
8        map(i/100,j) = {unique(gotcha2(gotcha1 == j))};
9      end
10   end

In line 8 will this varible create basically a dictionary inside a dictionary?

[dpb]

Dunno what you meah by "dictionary" here...

You would create a cell array of 5xlength each element of which containing the output of the call to unique...with the caveat that the number of columns in the array map will be the value of the maximum that length will have been over the loop on i. You will end up with empty cells in those locations for which i,j is not covered.

Also, do NOT use "length" as a variable; it's a builtin MATLAB function.

It's not in a toolbox I have so not sure, but I'd guess there's a good chance that map is used in one or more toolboxes as well...

[Image Analyst]

Please attach your .mat files. Use the paper clip icon to attach data_i.mat, and for line 3, that won't work because the first argument has to be your .mat filename. Your code will create a cell array with 5 rows and however many unique numbers are in the row with the most unique numbers in array gotcha2. I have no idea what you're after here. It would be good for you to attach the .mat files, and say what you'd like map to be after the code finishes.

[Walter Roberson]

thisfile = sprintf('load_%d.mat', i);
nextfile = sprintf('load_%d.mat', i+100);
A = load(thisfile, 'gotcha');
B = load(nextfile, 'gotcha');

[Sydney Richardson]

Yes these answers helped me figure it out thanks you everyone!