How to improve double precision?

I have made below code

a=11;
b=256;
c=a/b

and the output said c=0, which was not I had expected

So I have used cast operator

a=11;
b=256;
c=double(a/b)

and the result returns the same value; 0

I have searched Matlab document and found that the default precision of double data type is 32

so It should return 0.04296875 instead of 0. But still get 0 for this kind of codes

How to fix it properly?

[dpb]

>> format long, format compact
>> a=11;b=256;c=a/b
c =
   0.042968750000000
>> 

What does

whos a b c
get(0,'format')

return?

[NoYeah]

oh sorry, It was mean return of c

[dpb]

I asked you to type in teh above commands on your system and tell us what you get?

[Stephen23]

"I have searched Matlab document and found that the default precision of double data type is 32"

Highly unlikely. Can you please provide a link to the MATLAB documentation where this value comes from?

Answer 1

[Walter Roberson]

Either your a or your b is type uint8. When you work with int8, int16, int32, uint8, uint16, or uint32, then the operands are converted to double(), and the operation is done, and then the result is converted back to the most restricted type used.

Operations for int64 and uint64 are handled differently in some, because 64 bit integers cannot be converted to double without losing precision.

[dpb]

Could be any of the int classes, of course...what the

whos a b c

would have told us is which one(s) OP had...what OP didn't show was how a, b were created to begin with to become int class