Substitute syms in 2D array to have 3D array

I have a 2D array of syms and I want to substitute the syms variables with 1D array. How do i do it? If a form a loop it takes a long runtime.

sample code:

syms a b c
arr=[0 0 0;0 0 0;a b c];
a=[1 2 3 4 5]';
b=[2 3 4 5 6]';
c=[5 6 7 8 9]';
subs(arr)

The output should be a 3x3x5 matrix. Please help

I have the following code using loops:

    syms a b c
arr=[0 0 0;0 0 0;a b c];
J=zeros(3,3,5);
a1=[1 2 3 4 5]';
  b1=[2 3 4 5 6]';
  c1=[5 6 7 8 9]';
for i=1:5
a=a1(i);
b=b1(i);
c=c1(i);
J(i)=subs(arr);
end

[Azzi Abdelmalek]

It's not clear

Answer 1

[Walter Roberson]

subs() is not able to do this for you, as you need to replicate the other elements of the array. I do not think you will be able to do this without a loop (though you can probably hide the loop using arrayfun())

[Walter Roberson]

You initialize J as numeric zeros of size (3,3,5), but you assign to J(i) which would be J(i,1,1) a single numeric location.

Try

syms a b c
arr=[0 0 0;0 0 0;a b c];
a1=[1 2 3 4 5]';
b1=[2 3 4 5 6]';
c1=[5 6 7 8 9]';

J = double( arrayfun(@(aval, bval, cval) subs(arr, {a, b, c}, {aval, bval, cval}), a1, b1, c1) );

You might have to use

J = double( cell2mat( arrayfun(@(aval, bval, cval) subs(arr, {a, b, c}, {aval, bval, cval}), a1, b1, c1, 'Uniform', 0) ));

Answer 2

[Saurav Agarwal]

Taking a loop take a lot of time.. is there an alternate way? please help.

[Walter Roberson]

I cannot think of any way of doing this that does not involve a loop.

If you show the loop that you have coded, we can examine it and see if we can suggest improvements.

[Saurav Agarwal]

I have edited the question to show the code using loop.