Substitute syms in 2D array to have 3D array
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have a 2D array of syms and I want to substitute the syms variables with 1D array. How do i do it? If a form a loop it takes a long runtime.
sample code:
syms a b c
arr=[0 0 0;0 0 0;a b c];
a=[1 2 3 4 5]';
b=[2 3 4 5 6]';
c=[5 6 7 8 9]';
subs(arr)
The output should be a 3x3x5 matrix. Please help
I have the following code using loops:
syms a b c
arr=[0 0 0;0 0 0;a b c];
J=zeros(3,3,5);
a1=[1 2 3 4 5]';
b1=[2 3 4 5 6]';
c1=[5 6 7 8 9]';
for i=1:5
a=a1(i);
b=b1(i);
c=c1(i);
J(i)=subs(arr);
end
Réponse acceptée
Walter Roberson
le 22 Déc 2012
subs() is not able to do this for you, as you need to replicate the other elements of the array. I do not think you will be able to do this without a loop (though you can probably hide the loop using arrayfun())
1 commentaire
Walter Roberson
le 23 Déc 2012
You initialize J as numeric zeros of size (3,3,5), but you assign to J(i) which would be J(i,1,1) a single numeric location.
Try
syms a b c
arr=[0 0 0;0 0 0;a b c];
a1=[1 2 3 4 5]';
b1=[2 3 4 5 6]';
c1=[5 6 7 8 9]';
J = double( arrayfun(@(aval, bval, cval) subs(arr, {a, b, c}, {aval, bval, cval}), a1, b1, c1) );
You might have to use
J = double( cell2mat( arrayfun(@(aval, bval, cval) subs(arr, {a, b, c}, {aval, bval, cval}), a1, b1, c1, 'Uniform', 0) ));
Plus de réponses (1)
Saurav Agarwal
le 23 Déc 2012
2 commentaires
Walter Roberson
le 23 Déc 2012
I cannot think of any way of doing this that does not involve a loop.
If you show the loop that you have coded, we can examine it and see if we can suggest improvements.
Voir également
Catégories
En savoir plus sur Number Theory dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!