Sizing array to add to a 3D array

Aloha!

I have a relatively big array (sorted_celldata) with all my data (12 columns, 248976 rows), its contains data from the follow up of 23819 cells through the time.

I would like to simplify the access to the data by generating an array for each single cell (the id of each cell in in column 12 of sorted_celldata), and then store them in a 3 dimension array.

Here my code:

for p=1:max(sorted_celldata(:,12))

cell_idxlist = find (sorted_celldata(:,12) == p); % to look in which line I have data from cell p

celldata = sorted_celldata (cell_idxlist,:); % to generate a array with all data from cell p

nb_of_rows = size (celldata,1); % I put this line because of the error message below, trying to adjust the since of the arrays

nb_of_columns = size (celldata,2); % I put this line because of the error message below, trying to adjust the since of the arrays

celldata_arrays (nb_of_rows,nb_of_columns,p) = [celldata]; % here I generate my 3 dimension arrays, where each 3rd dimension is an array containing the data of a specific cell

end

Unfortunately, here the error message that I get:

Unable to perform assignment because the indices on the left side are not

compatible with the size of the right side.

Error in untitled9 (line 6)

celldata_arrays (nb_of_rows,nb_of_columns,p) = [celldata]

Answer 1

[Sudheer Bhimireddy]

You are changing the array size which is not how you do to store something. You are trying to store multi-dimensional array in a single field, that's why you are getting that error.

Choice 1:

% Change this line
celldata_arrays (nb_of_rows,nb_of_columns,p) = [celldata];   
% to
celldata_arrays (nb_of_rows,nb_of_columns,p) = 0;   
celldata_arrays (:,:,p) = celldata;   

This way you will have empty fields whenever nb_rows and nb_columns is greater than previous values.

Choice 2:

celldata_arrays {p,1} = celldata;   

Hope this helps.

[chann lagadec]

Thanks Sudheer,

I put this code now:

for p=1:max(sorted_celldata(:,12))

cell_idxlist = find (sorted_celldata(:,12) == p);

celldata = sorted_celldata (cell_idxlist,:);

nb_of_rows = size (celldata,1)

nb_of_columns = size (celldata,2)

celldata_arrays (nb_of_rows,nb_of_columns,p) = 0;

celldata_arrays (:,:,p) = celldata;

end

It's going 1 for loop correctly, but I got an error for the second loop (since size of the second array is different... If I understand correctlu-y, it should have put 0 on the empty fields):

"Unable to perform assignment because the size of the left side is 100-by-12 and

the size of the right side is 75-by-12.

Error in untitled9 (line 11)

celldata_arrays (:,:,p) = celldata; "

Since I can have a maximum of 120 rows, I wrote this code:

for p=1:max(sorted_celldata(:,12))

cell_idxlist = find (sorted_celldata(:,12) == p);

celldata = sorted_celldata (cell_idxlist,:);

celldata_arrays (120,12,p) = 0;

celldata_arrays (:,:,p) = celldata;

end

But it does not even run through the first loop:

Unable to perform assignment because the size of the left side is 120-by-12 and

the size of the right side is 75-by-12.

Error in untitled9 (line 11)

celldata_arrays (:,:,p) = celldata;

Thanks for your precious help

[chann lagadec]

I just try the second solution... and bigo, it's working just find!!!!

Thanks a lot for your help.

[madhan ravi]

bigo , find??

[chann lagadec]

sorry... "Bingo" (meaning "jackpot")

It's working perfectly, I could start the analyse... It's actually running... heating up my computer while it's already 34°C in the room (hot weather today!)