Hello,
I input my data as three different variables, acc, gyr, and mag. I want a small amount of code that makes all three variables the length of the shortest variable.
For example, if acc is 12000x1 and gyr is 12000x1, but mag is 12001x1, how can i automate deleting this row to make the vectors all the same length.
Thank you for your help,
Adam

 Réponse acceptée

Matt J
Matt J le 6 Août 2020
Modifié(e) : Matt J le 6 Août 2020

1 vote

One way,
collection = {acc,gyr,mag};
minlen = min(cellfun('length',collection));
clipped=cellfun(@(z)z(1:minlen),collection,'uni',0);
[acc,gyr,mag]=deal(clipped{:})

5 commentaires

Adam Levschuk
Adam Levschuk le 6 Août 2020
HI matt thanks for the help, if acc was a 12000x3 vector, gyr is 12000x3 vector, and mag is a 12001x3 vector, how would this change the code?
Adam
Adam Levschuk
Adam Levschuk le 6 Août 2020
other than that and the vectors getting transosed it works. Any idea how to make this to handel the 12000x3 and 12001x3 vectors?
Matt J
Matt J le 7 Août 2020
Like so,
collection = {acc,gyr,mag};
minlen = min(cellfun(@(z)size(z,1),collection));
clipped=cellfun(@(z)z(1:minlen,:),collection,'uni',0);
[acc,gyr,mag]=deal(clipped{:})
Adam Levschuk
Adam Levschuk le 7 Août 2020
thanks matt
Matt J
Matt J le 7 Août 2020
but note that,
>> isvector(rand(12000,3))
ans =
logical
0

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Image Analyst
Image Analyst le 7 Août 2020

1 vote

Maybe this:
lastRow = min([length(acc), length(gyr), length(mag)])
% Crop
acc = acc(1 : lastRow);
gyr = gyr(1 : lastRow);
mag = mag(1 : lastRow);

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R2020a

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