Proportion of Failures Test
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I was reading the following website:
It states:
The result of the test is to accept if
PValuePOF<F(TestLevel)
Should this actually be
F(LR_POF)<F(TestLevel)
For example, I calculated the following in excel:
Table 3 POF
LR_POF 0.0168 = =-2*((251-13)*LN((251*(1-0.05))/(251-13))+13*LN((251*0.05)/13))
F(LR_POF) 0.1031 =1-CHIDIST(LR_POF,1)
PValuePOF 0.8969 =1-F_LR_POF
F(TestLevel) 0.6703 =1-CHIDIST(0.95,1)
Result accept =IF(F_LR_POF<F_TestLevel,"accept","reject")
I look forward to your response.
Kindest Regards,
Clarissa
0 commentaires
Réponses (0)
Voir également
Catégories
En savoir plus sur Text Analytics Toolbox dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!