Effacer les filtres
Effacer les filtres

undefined variable even with equal sign, tried to see if it was the () but no luck

3 vues (au cours des 30 derniers jours)
Jarren Berdal
Jarren Berdal le 9 Août 2020
if(n)>=(2)
any(a(k)== 43)&&any(a(k)==32);
XXXIIPBS = find(a==32);
XLIIIPBS = find(a==43);
PBS = (A(XXXIIPBS).*a(XXXIIPBS))+(A(XLIIIPBS).*(a(XLIIIPBS)));
end
if (n)>=(3)
any(a(k)==10)&&any(a(k)==21)&&any(a(k)==32);
Xeggavosand = find(a==10);
XXIeggavosand = find(a==21);
XXXIIeggavosand = find(a==32);
EVS = A(Xeggavosand).*a(Xeggavosand)+A(XXIeggavosand).*a(XXIeggavosand)+A(XXXIIeggavosand).*a(XXXIIeggavosand);
end
if (n)>= (4)
any(a(k)==10)&&any(a(k)==54)&&any(a(k)==65)&&any(a(k)==76);
any(a(k)==87)&&any(a(k)==98)&&any(a(k)==12)&&any(a(k)==34);
LXXXVIISM = find(a==87);
XIISM = find(a==12);
XCVIIISM = find(a==98);
XXXIVSM = find(a==34);
SBSMO = (A(LXXXVIISM).*a(LXXXVIISM))+((A(XIISM).*a(XIISM)))+(A(XXXIVSM).*a(XXXIVSM))+(A(XCVIIISM).*a(XCVIIISM));
Xom = find(a==10);
LIV = find(a==54);
LXV = find(a==65);
LXXVI= find(a==76);
OM = ((A(Xom).* a(Xom))+(A(LIV).*a(LIV))+(A(LXV).*a(LXV))+(A(LXXVI).*(a(LXXVI))));
end
if PBS >= 107
disp('Peanut Butter Sandwich: 1 Peanut butter jar, 2 slices of bread')
end
if EVS >= 95
disp('EGGAVOCADOSANDWICH: 1 egg, 1 avocado, 2 slices of bread')
end
if OM >= 215
disp('Spinich Cheese Omlet: 2 eggs, 1 cup of spinach, 1/4 tbs of butter, 1 slice of cheese')
end
if SBSMO >= 318
disp ('Strawberry Banna Smoothie: 2 cups of strawberries, 1 banana, 1 cup of milk, 1 cup of ice')
end
disp('Recipes available to make are:')
my input is:
How many ingredients do you have? 2
Type code of Ingrediant #1: 32
Type quantity of Ingrediant #1: 4
Type code of Ingrediant #2: 43
Type quantity of Ingrediant #2: 1
Peanut Butter Sandwich: 1 Peanut butter jar, 2 slices of bread
Undefined function or variable 'EVS'.
Error in SFSU918374852_FinalProject (line 54)
if EVS >= 95
  1 commentaire
Walter Roberson
Walter Roberson le 9 Août 2020
Modifié(e) : Walter Roberson le 9 Août 2020
any(a(k)== 43)&&any(a(k)==32);
That evaluates a condition, figuring out whether the condition is true or false. Then, it throws away the result of the expression. You are not testing the result, and you are not displaying the result, and you are not assigning the result to a variable.
Likewise for
any(a(k)==10)&&any(a(k)==54)&&any(a(k)==65)&&any(a(k)==76);

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Réponses (1)

Cris LaPierre
Cris LaPierre le 9 Août 2020
EVS is only defined in the case where n>=3 (btw, you don't need the parentheses around n and 3). What is your value of n? If it's less than 3, this is your problem.

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