Force tiledlayout('flow') to layout vertically

121 vues (au cours des 30 derniers jours)
Scott
Scott le 16 Août 2020
Réponse apportée : Dave B le 17 Mar 2023
The problem I have with tiledlayout('flow') is that it it will often end up arranging the plots in a 2x2 grid, rather than a 4x1.
I understand tiledlayout('flow') tries to keep a 4:3 ratio for plots, but this is not useful for my data.
Tiledlayout(x,1) won't work because I don't know x beforehand.
I had hoped that in the case of tiledlayout(x,1) I could set the GridSize property, but it is read only.
Any suggestions on how to overcome this would be helpful, thank you.

Réponse acceptée

Dave B
Dave B le 17 Mar 2023
Starting in R2023a you can use the 'horizontal' and 'vertical' tile arrangements to accomplish layouts that are dynamically sized but only in one direction. More information available in the tiledlayout documentation.
figure(1)
t=tiledlayout('horizontal');
nexttile
plot(rand(1,10))
nexttile
bar(rand(1,10))
nexttile
scatter(rand(1,10),rand(1,10))
figure(2)
t=tiledlayout('vertical');
nexttile
plot(rand(1,10))
nexttile
bar(rand(1,10))
nexttile
scatter(rand(1,10),rand(1,10))

Plus de réponses (1)

Srivardhan Gadila
Srivardhan Gadila le 20 Août 2020
Based on the above information and the documentation of tiledlayout & nexttile, for this particular problem you can make use of the 'nexttile(span)' syntax as follows:
% Let the max number tiles are maxTiles = 1000 (>>n or just >=n)
maxTiles = 1000;
x = linspace(0,30);
tiledlayout('flow')
n = randi([1 10]);
for i=1:n
nexttile([1 maxTiles])
y = rand(1,numel(x));
plot(x,y)
end
  1 commentaire
Scott
Scott le 20 Août 2020
Thank you! That does work flawlessly indeed. I did read that documentation before, and I would not have thought to use it in this way.

Connectez-vous pour commenter.

Produits


Version

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by