Error::Assignment has more non-singleton rhs dimensions than non-singleton subscripts

I m trying the following code :

for o=1:n x=length(find(cell2mat(mi(1,o)))); m(1,o)=[m(1,o),x]; end

and I get this error.mi and m are cell arrays and both has dimensions of (1xn)

The above code has worked for a similar assignment but a different function on line 2. please help. Thanks!

[Matt J]

Just re-formatting this for better readability,

for j=1:n 
  x=length(find(cell2mat(mi(1,j)))); 
  m(1,j)=[m(1,j),x]; 
end

[Tripti Malviya]

thank u!

Answer 1

[Matt J]

Instead of

   m(1,j)=[m(1,j),x];

I think you meant

   m{1,j} = x;

Otherwise, clarify what you want m{1,j} to contain.

[Tripti Malviya]

actually this is what i want to do but the way is wrong. And if i use this statement

m{1,j} = x;

it gives me another error 'Conversion to cell from double is not possible'

[Matt J]

I'm skeptical that you've really done

 m{1,j} = x;

I suspect what you've really done is used brackets '()' instead of braces '{}'

m(1,j) = x;

The latter would definitely explain the 'Conversion to cell' error.

[Tripti Malviya]

i got it by the way you told. thank u so much. i did it by another way also - instead of cell i created a 1-D array and stored values as-

     for o=1:n
         m(1,o)=length(find(cell2mat(mi(1,o))));
     end

Thanks once again :)

[Matt J]

That does make more sense. Even better would be to do

     for o=1:n
         m(1,o)=nnz(mi{1,o});
     end

Or, if you want to hide the for-loop

   m=cellfun(@nnz,mi);