problem with back-substitution code
28 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Sienna Phillips
le 20 Août 2020
Commenté : Shaima Al-Shalwi
le 5 Sep 2022
I want to make an algorithm for back substitution and am testing it on some U and some b. when I call the function though it says U is not defined. Can anyone see where I have made an error? I am very new to MATLAB!
%--INPUTS------------------------------------------------------------------
%
% U - upper triangular matrix
% b - column vector
%
%--OUTPUT------------------------------------------------------------------
%
% b - solution x of Ux=b, stored in b
%
function b=myBackwardSubstitution(U,b)
d=size(U,1);
U=[1 2 3; 4 5 6; 7 8 9];
b=[1;2;3];
for i=1:d
for j=i+1:d
b(i)=b(i)-L(i,j)*b(j);
end
b(i)=b(i)/L(i,i);
end
0 commentaires
Réponse acceptée
Alan Stevens
le 20 Août 2020
Define U and b outside function to which you pass them.
Define L.
%--INPUTS------------------------------------------------------------------
%
% U - upper triangular matrix
% b - column vector
%
%--OUTPUT------------------------------------------------------------------
%
% b - solution x of Ux=b, stored in b
%
% Define U and b outside of function.
U=[1 2 3; 4 5 6; 7 8 9];
b=[1;2;3];
% Call function
b = myBackwardSubstitution(U,b);
function b=myBackwardSubstitution(U,b)
d=size(U,1);
for i=1:d
for j=i+1:d
% You haven't defined L
b(i)=b(i)-L(i,j)*b(j);
end
b(i)=b(i)/L(i,i);
end
end
1 commentaire
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Characters and Strings dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!