Evaluating 2D function on 2D grid without using "for" loops

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Luqman Saleem
Luqman Saleem le 21 Août 2020
Commenté : Sara Boznik le 22 Août 2020
I have a function f(x,y) and I want to evaluate it on x,y grid. For example,
f = @(x,y) x^2+y^2;
x = 1:10;
y = 1:5;
%one way to do it is using for loops.
for x=1:10
for y=1:5
result(x,y) = f(x,y);
end
end
Is there any way do it without using "for" loops?
  1 commentaire
Stephen23
Stephen23 le 22 Août 2020
"Is there any way do it without using "for" loops?"
Why do you want to avoid for loops? Contrary to what some beignners think, (well-written) for loops are not slow.
Is result preallocated before the loops?

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Réponses (1)

Sara Boznik
Sara Boznik le 21 Août 2020
f = @(x,y) x.^2+y.^2;
x = 1:10;
y = 1:5;
[X,Y] = meshgrid(x,y);
meshc(X, Y, f(X,Y))
grid on
You can try that.
Best of luck.
  2 commentaires
Luqman Saleem
Luqman Saleem le 21 Août 2020
Actually, the original function is very large and I will have to put (.) in front of all "^" or "*" operators. It also involves matrix multiplication, so, it will just be very messy if I try to put ".". Is there any way to avoid doing it?
Sara Boznik
Sara Boznik le 22 Août 2020
Sorry, I do not know faster way

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