Effacer les filtres
Effacer les filtres

Copy cells a variable number of times

4 vues (au cours des 30 derniers jours)
EldaEbrithil
EldaEbrithil le 2 Sep 2020
Commenté : EldaEbrithil le 2 Sep 2020
Hi all
i have this code
for i=1:length(a)
C(i)=repmat(b(i),1,a(i))
end
where b is a cell array
16x5 double
16x5 double
13x5 double
and a is an array
[101,17,1]
i want to copy the first cell 101 times, the second cell, 17 times and last cell only one time, but using the upper code i can't do that...any idea?
Thank you for the help!!
Regards
  4 commentaires
Stephen23
Stephen23 le 2 Sep 2020
Modifié(e) : Stephen23 le 2 Sep 2020
"the cell and the matrix inside it"
That seems very unusual. So given this cell array:
C = {X,Y,Z}
you want to repmat both the cells and the matrices to get this:
{[X,X,X...X],[X,X,X,...X],...,[X,X,X,...X],[Y,Y,Y,...Y],[Y,Y,Y,...Y],...,[Y,Y,Y,...Y],[Z,Z,Z,...,Z],...,[Z,Z,Z,...Z]}
I would have expected either of these:
{X,X,...,X,Y,Y,...Y,Z,Z,...Z} % repmat the cells themselves
{[X,X,..,X],[Y,Y,...,Y],[Z,Z,...,Z]} % repmat the arrays inside the cells
EldaEbrithil
EldaEbrithil le 2 Sep 2020
Modifié(e) : EldaEbrithil le 2 Sep 2020
Yes in pratical terms i want something like that:
16x5 double
16x5 double
.
.(99 times)
.
16x5 double
16x5 double
.
.(15 times)
.
13x5 double

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Réponse acceptée

David Hill
David Hill le 2 Sep 2020
for i=1:length(a)
C{i}=repmat(b{i},1,a(i));
end
  4 commentaires
David Hill
David Hill le 2 Sep 2020
count=1;
for i=1:length(a)
for k=1:a(i)
C{count}=b{i};
count=count+1;
end
end
EldaEbrithil
EldaEbrithil le 2 Sep 2020
This is what i was looking for !!
Thank you so much David!!

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Plus de réponses (1)

Steven Lord
Steven Lord le 2 Sep 2020
To replicate the cells you can use repmat or repelem depending on whether you want ABCABCABCABC... or AAAABBBBCCCC ... In other words, how do you want the replicates to be collated? Suitable for stapling into packets or suitable for making stacks of loose handouts for students to select from piles?
X = {1:3, 4:7, [8 9]}; % A is 1:3, B is 4:7, C is [8 9]
Y1 = repmat(X, [1 2]) % ABCABC
Y2 = repelem(X, [2 3 4]) % AABBBCCCC
Or do you want to replicate the contents of the cells?
X2 = {repmat(1:3, [2 1]), repmat(4:7, [3 3]), repmat([8 9], 1, 4)}
% X2 contains a 2-by-3, a 3-by-12, and a 1-by-8

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