Effacer les filtres
Effacer les filtres

Amplitude Error in amplitude Spectrum of FFT

8 vues (au cours des 30 derniers jours)
ong
ong le 16 Jan 2013
Hello
I'm currently working on FFT on cosine and sine function. I want to get the FFT graph to be plotted. The graph of the FFT looks fine except that the value of the amplitude were a bit off.
The amplitude was suppose to be '1', however, at different frequency, the amplitude will change from 0.8 to 1.5.
The code looks like this: Fs=1000 t=0:1/Fs:1;
NFFT = 2^nextpow2(length(x)); y = fft(x,NFFT)/length(x); y = y(1:NFFT/2+1); my = 2*abs(y); f = Fs/2*linspace(0,1,NFFT/2+1);
plot(handles.freqdomain,f,my) xlabel('Frequency(Hz)') grid on
Any help is appreciated. Thanks in advance.

Réponse acceptée

Wayne King
Wayne King le 16 Jan 2013
Modifié(e) : Wayne King le 16 Jan 2013
I suspect that your frequency of interest is simply not falling on a DFT bin directly. Why do you think you need to use a power of two for the DFT?
For example, if I have data sampled at 1 kHz and I have 1000 points, then frequency increment in DFT bins is 1 Hz (the bins are 1 Hz apart) so a frequency of 100 Hz for example will fall directly on a bin.
Fs = 1000;
t = 0:1/Fs:1-1/Fs;
x = 1.5*cos(2*pi*100*t);
xdft = fft(x);
freq = 0:Fs/length(x):Fs/2;
xdft = xdft(1:length(x)/2+1)./length(x);
xdft(2:end) = 2*xdft(2:end);
plot(freq,abs(xdft))
See that the magnitude is estimated exactly. Now watch what happens when I pad to 1024:
xdft = fft(x,1024);
freq = 0:Fs/length(xdft):Fs/2;
xdft = xdft(1:length(xdft)/2+1)./length(x);
xdft(2:end) = 2*xdft(2:end);
plot(freq,abs(xdft))
by padding to 1024, I have now made the frequency of interest fall between DFT bins and that makes my amplitude estimate inaccurate.
in the Signal Processing Toolbox documentation

Plus de réponses (1)

ong
ong le 21 Avr 2013
As mention above,
xdft = xdft(1:length(x)/2+1)./length(x);
xdft(2:end) = 2*xdft(2:end);
What is the purposes of dividing by length(x) when xdft(1:length(x)/2+1) perform the task of removing the other symmetric half of fft?
I know that xdft(2:end) = 2*xdft(2:end) is for the purpose of multiplying all frequency by 2 except 0 and Nyquist freq. But why do you still have to do this steps?

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