For Ax=b, How do I make LU decomposition (A=L*U) without using lu function. For example, A is nxn matrix and bis nx1 matrix.

23 vues (au cours des 30 derniers jours)
clc
clear
A=rand(5)
b=rand(5,1);
A(2:3,1)
n=length(A)
U=A;
for i=1:n
k=i+1
i
U(k:n,i)=U(k:n,i)-U(i,i)*(U(k:n,i)/U(i,i))
end
for k= 1:n
L(k+1:n,k)=A(k+1:n,k)/A(k,k)
end
This is what I have try so far, I am very new to MATLAB like 2 week and genuinely struggle here.

Réponse acceptée

David Hill
David Hill le 5 Sep 2020
function [L,U] = mylu(A)
n = size(A,1);
for k = 1:n
if A(k,k)==0
warning('LU factorization fails');
L = []; U = []; return;
end
i = k+1:n;
A(i,k) = A(i,k)/A(k,k);
A(i,i) = A(i,i)-A(i,k)*A(k,i);
end
L = tril(A,-1)+eye(n); U = triu(A);

Plus de réponses (0)

Catégories

En savoir plus sur Linear Algebra dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by