Can you use the 'format long' command in the 'fprintf' command?

I would like to have variable 'x' formated using the 'format long' command when it is printed using fprintf. However, I am unable to place it between the % and f values of ('%f',x) since 'format long' begins with an f. I have tried using '.15' between % and f, however, the output values are not aligned when the numbers infront of the decimal place increase (see below). Can 'format long' be used in fprintf? If not, how can I keep the numbers in front of the decimal place the same length (in this example, '08' for the last three entries)?

sqrt of a (x)                       error(e)     iteration(s)
32.500000000000000    9.923e+02            1 
17.234615384615385    2.330e+02            2 
10.474036101145005    4.571e+01            3 
8.292191785986859    4.760e+00            4 
8.005147977880979    8.239e-02            5 
8.000001655289593    2.648e-05            6 

Answer 1

[Stephen23]

"Can 'format long' be used in fprintf?"

No.

"If not, how can I keep the numbers in front of the decimal place the same length..."

You can align numbers by specifying the field length:

>> M = [32.5,9.923e+02,1;17.234615384615385,2.330e+02,2;10.474036101145005,4.571e+01,3;8.292191785986859,4.760e+00,4;8.005147977880979,8.239e-02,5;8.000001655289593,2.648e-05,6];
>> fprintf('%18.15f   %.3e   %d\n',M.') % default: pad with spaces
32.500000000000000   9.923e+02   1
17.234615384615385   2.330e+02   2
10.474036101145005   4.571e+01   3
 8.292191785986859   4.760e+00   4
 8.005147977880979   8.239e-02   5
 8.000001655289593   2.648e-05   6
>> fprintf('%018.15f   %.3e   %d\n',M.') % optional: pad with zeros
32.500000000000000   9.923e+02   1
17.234615384615385   2.330e+02   2
10.474036101145005   4.571e+01   3
08.292191785986859   4.760e+00   4
08.005147977880979   8.239e-02   5
08.000001655289593   2.648e-05   6