Explicit indices for k-fold partitioning
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Is there any way to explicity provide the indices of each partition in a k-fold partition? I'd like to find optimal hyperparameters, but all the methods seem to either sequentially or randomly divide up the data. My data evolves over time, where each time step has a different number of observations. Doing things either sequentially or randomly results in 'looking into the future'. I'd like the partitions to reflect the information I have up to that time, and predict the response for next time to obtain a kfoldloss.
(Time itself has no relevance however, so this isn't amenable to time-series type analysis. It's a classification problem)
thanks in advance
anthony
8 commentaires
Anthony Diaco
le 11 Sep 2020
Adam Danz
le 11 Sep 2020
It sounds like you need to train on partition n-1 and test on partition n where the data in n-1 occured before n. Is that correct?
Anthony Diaco
le 11 Sep 2020
Adam Danz
le 11 Sep 2020
If you group the data by temporal segments using a grouping variable, I think the stratified partitions I mentioned in my answer is the way to go but I haven't done what you're doing so I can't be certain.
Anthony Diaco
le 11 Sep 2020
Adam Danz
le 14 Sep 2020
Anthony Diaco, I looked deeper into this today. With stratified sampling, the partitions ensure that each group is represented equally or close to equal. It doesn't sound that that's what you're looking for.
I think you should make your own partitions.
I'll update my answer with more detail.
Anthony Diaco
le 14 Sep 2020
Anthony Diaco
le 14 Sep 2020
Réponses (1)
Perhaps something like
x = 1:100; % demo vector
k = 5; % 5-partitions
folds = cell(k,1);
for i = 1:k
folds{i} = x(i:k:end);
end
Though, those partitions are far from randomized but they maintain temporal order. To fix that, you could 1) create a grouping variable for each segment, randomize the segments, and the execute the loop above on the randomized segments.
Alternatively, you could use stratified sampling within subgroups using
but that only ensure that each group is represented equally, it will not maintain the temporal order of your data.
1 commentaire
Anthony Diaco
le 11 Sep 2020
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