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Mahesh Taparia
on 14 Sep 2020

Hi

In general, in any neural network, the network tries to learn the weights which can reduce the cost/ loss function. The gradients are updated iteratively by using the derivative of loss function with respect to weights.

Usually for a fix input, calculating gradients of loss with respect to input is not meaningful because if input is fix, then d(loss)/d(Input) is not defined. If the network is feed with 2 different input sequence, in this case you can find the gradient by calculating (Loss2-Loss1)/(X2-X1), where Loss is the value of network loss with respect to input X. There is no use of this while training the network.

Hope it will helps!

Mahesh Taparia
on 17 Sep 2020

Hi

Mostly the neural network is highly non linear which consists of several activation functions.As of now there is no direct function which can calculate the gradient of the network output with respect to the network input. The approach is to derive the equations of derivative of the network. However, you can use the trained network which contains the trained weights and the used activations function. It can help in evaluation. For example, let F1 and F2 be the activation function and W1, W2 be the trained weights and B1 and B2 be the trained bias of each layer, then

Y=F2(W2*F1(W1*X+B1)+B2);

In this case, Y' (derivative with respect to X) can be written as:

Y'=W2*F2'{W2*(F1(W1*X+B1))+B2}*W1*{F1'(W1*X+B1)};

So, the nodes output are passed through the derivative of activation and the weights are getting multiplied. The nodes outputs and weights are stored in the trained network and for each layer. The derivatives of activation can be made as a separate function for simplicity.

Hope it will helps!

David Leather
on 24 Nov 2020 at 23:07

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