Solve equations by fsolve and with input anonymous function format
25 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
zongxian
le 12 Sep 2020
Réponse apportée : Steven Lord
le 12 Sep 2020
By the help document of Matlab, the example of fsolve is:
function F = root2d(x)
F(1) = exp(-exp(-(x(1)+x(2)))) - x(2)*(1+x(1)^2);
F(2) = x(1)*cos(x(2)) + x(2)*sin(x(1)) - 0.5;
fun = @root2d;
x0 = [0,0];
x = fsolve(fun,x0)
But now outer function transfer a anonymous function of fun, like:
fun = @(x,y) [x+y^2-5, 6*x^2+13*y-5]
Start value x0 = [1, 1]
How do I fit fsolve input format?
0 commentaires
Réponse acceptée
Steven Lord
le 12 Sep 2020
fun = @(x,y) [x+y^2-5, 6*x^2+13*y-5]
Since fsolve requires the function you pass into it to accept one input, a vector, you need an adapter.
g = @(xy) fun(xy(1), xy(2));
This has the interface fsolve requires and calls fun the way it expects to be called.
g([1 2]) % [0 27]
fun(1, 2) % [0 27]
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Linear and Nonlinear Regression dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!