# Replacing several values in multidimensional array simultaneously

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David Hoffmeyer on 14 Sep 2020
Edited: Bruno Luong on 14 Sep 2020
I have a multidimensional array, e.g.
A(:,:,1) = [1 2 3 ; 4 5 6];
A(:,:,2) = [7 8 9 ; 10 11 12];
I want to replace several of the values in this array with the same value simultaneously. Specifically I want to do this column-wise, the result should be e.g.
A(:,2,1) = [-1 ; -2];
A(:,3,2) = [-1 ; -2];
yielding
A(:,:,1) = [1 -1 3 ; 4 5 -1];
A(:,:,2) = [7 -2 9 ; 10 11 -2];
I attempted this by
B = [2 3]; C = [1 2];
A(:,B,C) = [-1 ; -2];
but it does not give the wanted result.
Any idea on how to do this without performing a for-loop?

Bruno Luong on 14 Sep 2020
Edited: Bruno Luong on 14 Sep 2020
A(:,:,1) = [1 2 3 ; 4 5 6];
A(:,:,2) = [7 8 9 ; 10 11 12];
s = size(A);
A(:, sub2ind(s(2:3),[2 3],[1 2])) = 0 % = [0 0; 0 0]

David Hoffmeyer on 14 Sep 2020
Thanks for your input. However, I have not been precise enough in my question. I need to replace a number of columns in the array with a column containing non-identical values (see the edited question), and not just 0. In that case your proposal does not work. Can you alter it correspondingly?
Bruno Luong on 14 Sep 2020
Just replace the RHS as I hint in my answer with "% = [0 0; 0 0]"
A(:, sub2ind(s(2:3),[2 3],[1 2])) = [[-1;-2], [-1;-2]]