How to find out the index number of particular value from three dimensional matrices
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A(:,:,1)= [1 0 0
0 1 0
1 0 1]
A(:,:,2)= [1 1 0
1 0 1
0 1 1]
A(:,:,3)= [1 0 1
0 0 1
1 1 0]
for i1=1:3
for j1=1:3
[a1(:,j1),b1(:,j1),c1(:,j1)]= ind2sub(size(A)==1,j1);
[a2(:,j1),b2(:,j1),c2(:,j1)]= ind2sub(size(A)==1,j1);
[a3(:,j1),b3(:,j1),c3(:,j1)]= ind2sub(size(A)==1,j1);
end
end
I have this three dimesional matix with different indices of three matrices. Now I want to find out the the rowcolumn and index number of each index of the matrices and store the value of 1st column of three matrices in one matrix and like so on. Means in a1 matrix 1st column of three signal should be stored. But the code is not working. Please suggest me to resolve this problem.
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Réponse acceptée
madhan ravi
le 14 Sep 2020
V = cell(size(A, 3), 1);
for k = 1 : size(A, 3)
[R, C] = find(A(:, :, k));
V{k} = [R, C];
end
celldisp(V) % V{1} first matrix indicating the first page and so on
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