Given that t is in increments 0.1 and goes from 0 to 20, how can I make a variable that consists of 5t^2?

4 vues (au cours des 30 derniers jours)
First I made x as:
>> t = 0:0.1:20
I have tried numerous ways to get a variable consisting of 5t^2 and have the same result. It ends up generating a 1x201 row vector with values from 0 to 2.
I believe it is only multiplying 5 by the 0.1 increment but not the actual values. Any solutions?
  2 commentaires
jessupj
jessupj le 14 Sep 2020
Modifié(e) : jessupj le 14 Sep 2020
5.*(0:0.1:20).^2
also perhaps try to adjust the way the output is showing, since the results are in range [0,2000] and it may look like [0,2] with a multiplier
format long g
Tyler Bodnarik
Tyler Bodnarik le 14 Sep 2020
It was a formatting issue I've got it now. Thank you!!

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David Hill
David Hill le 14 Sep 2020
  1 commentaire
Tyler Bodnarik
Tyler Bodnarik le 14 Sep 2020
For some reason its not giving me what 5t^2 should be. It keeps giving me a 1x201 row vector with values 0 to 2. It should have all the values of t get squared and multiplied by 5.

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