Effacer les filtres
Effacer les filtres

how to construct this equation in matlab?..for loop is best r something else..?

1 vue (au cours des 30 derniers jours)
Dhines
Dhines le 21 Jan 2013
http://latex.codecogs.com/gif.latex?H'_{i+1}(x,y)=round(\frac{H_{i}(2x-1,2y-1)+H_{i}(2x,2y-1)+H_{i}(2x,2y)}{4})-H_{i+1}(x,y)...
where i values varies 1 and 2.
x and y vale is 51 and 56 if i=1 ,i=2 mean x and y value is 76 and 78
[Merged from duplicate question]
http://latex.codecogs.com/gif.latex?H'_{i+1}(x,y)=round(\frac{H_{i}(2x-1,2y-1)+H_{i}(2x,2y-1)+H_{i}(2x,2y)}{4})-H_{i+1}(x,y)
for this equation i wrote this code.
x=51;
y=52;
H2'(x,y)=((H1(2x-1,2y-1)+H1(2x-1,2y)+H1(2x,2y)))/4
P=H2(x,y);
Q=H2'(x,y-H2(x,y);
here first of all H represents a horizontal subband of image 128 x 128. from this i'am derive detailed subbands H1,H2,H3. values 51 52,76 76,88 88. "i" values varies from 1 and 2.
  5 commentaires
Dhines
Dhines le 22 Jan 2013
see my updated question..there i said and constructed all
Walter Roberson
Walter Roberson le 22 Jan 2013
[New question has been merged into the original.]

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