How can I sort a matrix to match another matrix?

12 vues (au cours des 30 derniers jours)
Doli Swey
Doli Swey le 15 Sep 2020
Commenté : Doli Swey le 19 Oct 2020
Hello everybody,
I have a question regarding the sorting. I have 2 matrices, A and B. For example:
A = [11 1; 12 1; 13 1; 21 2; 23 2; 31 3; 33 3; 41 4]
B = [1; 2; 1; 3; 1; 4; 2; 3]
How can I sort A (randomly each time) that the 2 column of A is same with B? Such as:
A = [12 1; 23 2; 11 1; 31 3; 13 1; 41 4; 21 2; 33 3]
Stay happy and healty..

Réponse acceptée

Stephen23
Stephen23 le 16 Sep 2020
>> [~,idx] = sort(B);
>> [~,idx(idx)] = sort(A(:,2));
>> A = A(idx,:)
A =
11 1
21 2
12 1
31 3
13 1
41 4
23 2
33 3
  6 commentaires
Stephen23
Stephen23 le 17 Oct 2020
Modifié(e) : Stephen23 le 17 Oct 2020
"Do you have any idea that I can make this work?"
Possibly you could replace the RHS with a string (or character vector) of the number:
A(:,2) == num2str(k)
"...the first column contains strings, whereas second column is numbers."
I strongly recommend that you convert the data into a table, then the first column would be strings and the second column really would be numbers (not strings encoding numbers). Numeric data should be efficiently stored as numeric, which also makes processing it much easier.
Doli Swey
Doli Swey le 19 Oct 2020
I understand! Thank you so much. Have a wonderful day

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